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3241004551 [841]
4 years ago
12

A bird is flying north with a mass of 2.5kg has a momentum of 17.5kg m/s at what velocity is it flying

Physics
2 answers:
klasskru [66]4 years ago
8 0
Momentum = mass • velocity
v= 17.5/2.5
= 7 m/s
Law Incorporation [45]4 years ago
7 0

Answer:

v=7 m/s

Explanation:

momentum definition

The amount of movement or linear momentum is the product of velocity by mass. Velocity is a vector while mass is a scalar. As a result we obtain a vector with the same direction and direction as the velocity.

The magnitude of the momentum is calculated like this:

p=m*v  Formula (1)

where:

p: momentum  (kg*m/s)

m: mass  (kg)

v: velocity  (m/s)

Data

m = 2.5kg

p = 17.5kg m/s

Problem development

We replace the data in the formula (1)

17.5kg m/s = 2.5kg*v

17.5 kg*\frac{m}{s} = 2.5kg * v

v=\frac{17.5 kg*\frac{m}{s} }{2.5 kg}

v = 7 m/s

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An airplane went from 120 m/s to 180 m/s in 4.0 seconds. What was its acceleration?
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3 years ago
A particle is confined between rigid walls separated by a distance L = 0.167 nm. The particle is in the second excited state (n
ZanzabumX [31]

Answer:

The answer for a classical particle is 0.00595

Explanation:

The equation of the wave function of a particle in a box in the second excited state equals:

ψ(x) = ((2/L)^1/2) * sin((3*pi*x)/L)

The probability is equal to:

P(x)dx = (|ψ(x)|^2)dx = ((2/L)^1/2) * sin((3*pi*x)/L) = (2/L) * sin^2((3*pi*x)/L) dx

for x = 0.166 nm

P(x)dx = (2/0.167) * sin^2((3*pi*0.166)/0.167) * 100 pm = 0.037x10^-3

for x = 0.028 nm

P(x)dx = (2/0.167) * sin^2((3*pi*0.028)/0.167) * 100 pm = 11x10^-3

for x = 0.067 nm

P(x)dx = (2/0.167) * sin^2((3*pi*0.067)/0.167) * 100 pm = 3.99x10^-3

therefore, the classical probability is equal to:

(1/L)dx = (1/0.167)*100 pm = 0.00595

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3 years ago
Newton’s second law of motion states that an object with a heavier mass will have more acceleration than an object with a smalle
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This is true. I hope this helps! :) 
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Read 2 more answers
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