All categories

3 years ago

A bird is flying north with a mass of 2.5kg has a momentum of 17.5kg m/s at what velocity is it flying

Physics

2 answers:

klasskru [66]3 years ago

8 0

Momentum = mass • velocity
v= 17.5/2.5
= 7 m/s

Law Incorporation [45]3 years ago

7 0

Answer:

v=7 m/s

Explanation:

momentum definition

The amount of movement or linear momentum is the product of velocity by mass. Velocity is a vector while mass is a scalar. As a result we obtain a vector with the same direction and direction as the velocity.

The magnitude of the momentum is calculated like this:

p=m*v Formula (1)

where:

p: momentum (kg*m/s)

m: mass (kg)

v: velocity (m/s)

Data

m = 2.5kg

p = 17.5kg m/s

Problem development

We replace the data in the formula (1)

17.5kg m/s = 2.5kg*v

$17.5 kg*\frac{m}{s} = 2.5kg * v$

$v=\frac{17.5 kg*\frac{m}{s} }{2.5 kg}$

v = 7 m/s

You might be interested in

As part of your daily workout, you lie on your back and push with your feet against a platform attached to two stiff springs arr

zubka84 [21]

Answer:

$894.12\ \text{N}$

$284.013\ \text{J}$

Explanation:

U = Energy = 76 J

x = Displacement of spring = 0.17 m

k = Spring constant

Energy is given by

$U=\dfrac{1}{2}kx^2\\\Rightarrow k=\dfrac{2U}{x^2}\\\Rightarrow k=\dfrac{2\times 76}{0.17^2}\\\Rightarrow k=5259.51\ \text{Nm}$

Force is given by

$F=kx\\\Rightarrow F=5259.51\times 0.17\\\Rightarrow F=894.12\ \text{N}$

The magnitude of force must you apply to hold the platform is $894.12\ \text{N}$ .

Now $x=0.17+0.2=0.37\ \text{m}$

$U=\dfrac{1}{2}kx^2\\\Rightarrow U=\dfrac{1}{2}\times 5259.51\times 0.37^2\\\Rightarrow U=360.013\ \text{J}$

Additional energy

$360.013-76=284.013\ \text{J}$

8 0

2 years ago

There is a known potential difference between two charged plates of 12000 Volts. An object with a charge of 6.5 x 10-6 C charge

s344n2d4d5 [400]

Answer:

1.97 m/s.

Explanation:

From the question,

Using the law of conservation of energy,

The energy stored in the charged plate = Kinetic energy of the mass

1/2(qV) = 1/2mv².......................... Equation 1

Where q = charge, V = voltage, m = mass, v = velocity.

make v the subject of the equation

v = √(qV/m)......................... Equation 2

Given: q = 6.5×10⁻⁶ C, V = 12000 Volts, m = 0.02 kg

Substitute these values into equation 2

v = √(6.5×10⁻⁶×12000 /0.02)

v = √3.9

v = 1.97 m/s.

7 0

3 years ago

A force is directly proportional to what ?

pishuonlain [190]

It's mass and acceleration

4 0

3 years ago

In the diagram, q1 and q2 are both +5.00*10^-8 C. What is the electric field at point P? Include a + or - sign to indicate the d

Damm [24]

Answer:

1389.1

Explanation:

6 0

2 years ago

I have a test for my finals can y’all help me?

drek231 [11]

What’s the question? I may be able to help

7 0

2 years ago