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3 years ago

A bird is flying north with a mass of 2.5kg has a momentum of 17.5kg m/s at what velocity is it flying

Physics

2 answers:

klasskru [66]3 years ago

8 0

Momentum = mass • velocity
v= 17.5/2.5
= 7 m/s

Law Incorporation [45]3 years ago

7 0

Answer:

v=7 m/s

Explanation:

momentum definition

The amount of movement or linear momentum is the product of velocity by mass. Velocity is a vector while mass is a scalar. As a result we obtain a vector with the same direction and direction as the velocity.

The magnitude of the momentum is calculated like this:

p=m*v Formula (1)

where:

p: momentum (kg*m/s)

m: mass (kg)

v: velocity (m/s)

Data

m = 2.5kg

p = 17.5kg m/s

Problem development

We replace the data in the formula (1)

17.5kg m/s = 2.5kg*v

$17.5 kg*\frac{m}{s} = 2.5kg * v$

$v=\frac{17.5 kg*\frac{m}{s} }{2.5 kg}$

v = 7 m/s

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Answer:

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Explanation:

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2 years ago

What is the acceleration of a Ford Mustang GT that can go from 0.00 to 27.8<br> m/s in 5.15 seconds?

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2 years ago

Two coherent sources of radio waves, A and B, are 5.00 meters apart. Each source emits waves with wavelength 6.00 meters. Consid

Korolek [52]

Answer:

$z= 2.5 \ m$

$z = (1 \ m , 4 \ m )$

Explanation:

From the question we are told that

Their distance apart is $d = 5.00 \ m$

The wavelength of each source wave $\lambda = 6.0 \ m$

Let the distance from source A where the construct interference occurred be z

Generally the path difference for constructive interference is

$z - (d-z) = m \lambda$

Now given that we are considering just the straight line (i.e points along the line connecting the two sources ) then the order of the maxima m = 0

$z - (5-z) = 0$

=> $2 z - 5 = 0$

=> $z= 2.5 \ m$

Generally the path difference for destructive interference is

$|z-(d-z)| = (2m + 1)\frac{\lambda}{2}$

=> $|2z - d |= (0 + 1)\frac{\lambda}{2}$

=> $|2z - d| =\frac{\lambda}{2}$

substituting values

$|2z - 5| =\frac{6}{2}$

=> $z = \frac{5 \pm 3}{2}$

$z = \frac{5 + 3}{2}$

$z = 4\ m$

and

$z = \frac{ 5 -3 }{2}$

=> $z = 1 \ m$

=> $z = (1 \ m , 4 \ m )$

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3 years ago

A cylindrical water tank has a diameter of 9 ft and a height of 12 ft. the water surface is 2 ft from the top. about how much wa

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I think the answer your looking for is 636 ft ^3

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3 years ago

Read 2 more answers

A projectile is launched diagonally into the air and has a hang time of 24.5 seconds. Approximately how much time is required fo

Rasek [7]

Answer:

$t=12.25\ seconds$

Explanation:

<u>Diagonal Launch </u>

It's referred to as a situation where an object is thrown in free air forming an angle with the horizontal. The object then describes a known path called a parabola, where there are x and y components of the speed, displacement, and acceleration.

The object will eventually reach its maximum height (apex) and then it will return to the height from which it was launched. The equation for the height at any time t is

$x=v_ocos\theta t$

$\displaystyle y=y_o+v_osin\theta \ t-\frac{gt^2}{2}$

Where vo is the magnitude of the initial velocity, $\theta$ is the angle, t is the time and g is the acceleration of gravity

The maximum height the object can reach can be computed as

$\displaystyle t=\frac{v_osin\theta}{g}$

There are two times where the value of y is $y_o$ when t=0 (at launching time) and when it goes back to the same level. We need to find that time t by making $y=y_o$