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3241004551 [841]
3 years ago
12

A bird is flying north with a mass of 2.5kg has a momentum of 17.5kg m/s at what velocity is it flying

Physics
2 answers:
klasskru [66]3 years ago
8 0
Momentum = mass • velocity
v= 17.5/2.5
= 7 m/s
Law Incorporation [45]3 years ago
7 0

Answer:

v=7 m/s

Explanation:

momentum definition

The amount of movement or linear momentum is the product of velocity by mass. Velocity is a vector while mass is a scalar. As a result we obtain a vector with the same direction and direction as the velocity.

The magnitude of the momentum is calculated like this:

p=m*v  Formula (1)

where:

p: momentum  (kg*m/s)

m: mass  (kg)

v: velocity  (m/s)

Data

m = 2.5kg

p = 17.5kg m/s

Problem development

We replace the data in the formula (1)

17.5kg m/s = 2.5kg*v

17.5 kg*\frac{m}{s} = 2.5kg * v

v=\frac{17.5 kg*\frac{m}{s} }{2.5 kg}

v = 7 m/s

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Answer:

v = 15.65 m/s

Explanation:

We use conservation of mechanical energy between initial (i) and final (f) states:

Pi + KEi = Pf + KEf

At the top of the cave at the instant the bat starts to fall, there is only potential energy since the bat's velocity is zero.

Pi = m g h = 600 J

and the KEi = 0 J (no velocity)

Knowing the height of the cave's roof (12.8 m) , we can find the mass of the bat:

m = 600 J / (g 12.5) = 4.9 kg

Using conservation of mechanical energy, the final state is:

Pf + KEf = 600 J

with Pf = 0 (just touching the ground)

KEf= 1/2  4.9 (v^2)

and we solve for the velocity:

600 J = 0 + 1/2  4.9 (v^2)

v^2 = 600 * 2 / 4.9 = 244.9

v = 15.65 m/s

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2 years ago
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A 1500 kg car traveling 5.0 m/s collides head on with a 3000 kg truck traveling
Setler [38]
  • m1=1500kg
  • m_2=3000kg
  • v_1=5m/s
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Using law of conservation of momentum

\\ \sf\Rrightarrow m_1v_1-m_2v_2=(m1+m2)v_3

\\ \sf\Rrightarrow 1500(5)-3000(7)=(1500+3000)v_3

\\ \sf\Rrightarrow 7500-21000=4500v_3

\\ \sf\Rrightarrow -13500=4500v_3

\\ \sf\Rrightarrow v_3=-3m/s

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Explanation:

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