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Gennadij [26K]
3 years ago
9

Two 25.0N weights are suspended at opposite ends of a rope that passes over a frictionless pulley. What is the tension in the ro

pe?
Physics
1 answer:
goldenfox [79]3 years ago
8 0

Answer:

tension in rope = 25.0 N

Explanation:

  • Two forces act on the suspended weight. The force coming down is the gravitational force and the upward force by the tension in the rope.
  • Since the suspended weight is not accelerating so that the net force will be zero. Therefore the tension in the rope should be 25 N.

       ∑F = F - W = 0

       so

       F = W

       so tension in rope = F  = T  = 25 N

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eimsori [14]

Answer:

inertia

Explanation:

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3 years ago
check the file.........................................................................................................
White raven [17]

What is meant by the number of complete oscillation made by an oscillating body in 10 seconds is 500 complete oscillations is that the  frequency of the oscillating body is 50Hz

<h3>What is frequency?</h3>

Frequency of an oscillating body can be defined as the number of complete oscillations per unit time

Frequency is measured in hertz (Hz).

Also, the frequency of 1Hz is one oscillation per second.

frequency = number of oscillations/ time taken

frequency = 500/10 = 50 Hz

Thus, what is meant by the number of complete oscillation made by an oscillating body in 10 seconds is 500 complete oscillations is that the  frequency of the oscillating body is 50Hz

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6 0
2 years ago
Does the area of contact effect the frictional force . explain?​
OlgaM077 [116]

Answer:

The force due to friction is generally independent of the contact area between the two surfaces. This means that even if you have two heavy objects of the same mass, where one is half as long and twice as high as the other one, they still experience the same frictional force when you drag them over the ground.

Plz mark 5 star, thanks, and brainliest

3 0
3 years ago
Air having a pressure of 40 psig and a volume of 8 cu ft expands isothermally to a pressure of 10 psig. Find the external work p
DerKrebs [107]

Answer:

357.6 lb-ft

Explanation:

V = Volume = 8 ft³

dP = Change in pressure = (40-10) = 30 psig

Work done is given by

W=VdP\\\Rightarrow W=8\times (40-10)\\\Rightarrow W=240\ psig.ft^3

30\ psig=44.7\ psi\\\Rightarrow 1\ psi=\dfrac{30}{44.7}

So, converting to ft-lb

\dfrac{240}{\dfrac{30}{44.7}}=357.6\ lb-ft

The external work performed during the expansion is 357.6 lb-ft

7 0
4 years ago
Does temperature affect the amount of sugar that dissolved in tea? Why
Andrei [34K]

Answer:

Generally, a solute dissolves faster in a warmer solvent than it does in a cooler solvent because particles have more energy of movement. For example, if you add the same amount of sugar to a cup of hot tea and a cup of iced tea, the sugar will dissolve faster in the hot tea.

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3 years ago
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