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Ne4ueva [31]
3 years ago
13

Need by tomorrow please help

Mathematics
2 answers:
nikklg [1K]3 years ago
6 0
1    - 9
2   -28 
3    54
4    -100
5   -60
6     0
7   49
8   -135
9    -96
10   300
11    0
12    192
KIM [24]3 years ago
4 0
1) -9
2) -28
3)54
4) -100
5) -60
6) 0
7) 49
8) 135
9)-96
10) 300
11) 0
12) 192
13) $75 x 7 = $525
14) 5 yards x 3 = lost 15yards
You can draw a number line(start form zero), then go negative 5 units 3 times (3 plays). Then you should end up at -15
15) 2 x 6 = 12
16) $5 x 4 = 20
You might be interested in
owynn wants to buy a computer that normally costs $689.99 but is on sale for 5% off. If he waits two weeks the same computer wil
EastWind [94]
Sorry I don’t have a calculator with me atm but if you just put this into a calculator you’ll have the answer
So I use decimal multipliers for discounts to do this just change your percentage into a decimal with 100% as 1.00 so if it were increasing by 5% it would be 1.05 since it’s a sale the decimal would be 0.95 you can now multiply this to the original price to find this new price
So 689.99 x 0.95
If you follow this again for the 15% sale then the decimal multiplier would be 0.85
So 689.99 x 0.85
Just put these into a calculator and you’ll get your answers
7 0
3 years ago
In a class of 28 students, 12 earned an A on the final exam, 6 earned a B, 4 earned a C, and the remaining students failed. Base
Sedaia [141]

Answer:

  5/14 ≈ 35.7%

Step-by-step explanation:

(12 +6) = 18 of the 28 students earned an A or a B. So, the experimental probability that a student did not earn that grade is ...

  p(<B) = (28 -18)/28 = 10/28

  p(<B) = 5/14 ≈ 35.7%

6 0
3 years ago
A privately owned lake contains two types of game fish, bass and trout. The owner provides two types of food, A and B, for these
Vinvika [58]

Answer:

133 fishes

Step-by-step explanation:

Units of food A = 400 units

Units of food B = 400 units

Fish Bass required 2 units of A and 4 units of B.

Fish Trout requires 5 units of A and 2 units of B.

i. For food A,

total units of food A required = 2 + 5

                                                 = 7 units

number of bass and trout that would consume food A = 2 x \frac{400}{7}

                                               = 114.3

number of bass and trout that would consume food A = 114

ii. For food B,

total units of food B required = 4 + 2

                                                = 6 units

number of bass and trout that would consume food B = 2 x \frac{400}{6}

                                                 = 133.3

number of bass and trout that would consume food B = 133

Thus, the maximum number of fish that the lake can support is 133.

4 0
2 years ago
4-1/x divided by 16-1/xsquared
Vladimir [108]
4 - 1/x (16)-1/x 2  
4x-18/x
3 0
3 years ago
What is 110y+10=340 for algebra grade 7
algol [13]
<span> 110y+10=340

Subtract 10 from both sides 

110y=330 

Divide by 110 to get variable on its own 

</span>110y/110=330/110

y=3
7 0
3 years ago
Read 2 more answers
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