Answer:
![y=2x-10](https://tex.z-dn.net/?f=y%3D2x-10)
Step-by-step explanation:
We know that the line has a slope of 2 and it passes through the point (3, -4).
So, we can use the point-slope form:
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
Where m is the slope and (x₁, y₁) is a point.
So, let’s substitute 2 for m and (3, -4) for (x₁, y₁). This yields:
![y-(-4)=2(x-3)](https://tex.z-dn.net/?f=y-%28-4%29%3D2%28x-3%29)
Solve for y. Distribute the right:
![y+4=2x-6](https://tex.z-dn.net/?f=y%2B4%3D2x-6)
Subtract 4 from both sides. Therefore, our equation is:
![y=2x-10](https://tex.z-dn.net/?f=y%3D2x-10)
The discount is $1.19 unless you have to round up than it is $1.20. in order to solve this problem you would set up a proportion. So your proportion would be x over 7.99 = 15 over 100. Than you would cross multiply. 7.99*15=119.85. and 100*x=100x. than u divided both sides by a 100. than x= 1.19. which 1.19 is the discount.
Answer:
87.965 in.
Step-by-step explanation:
1) the formula of full arc is L=2π*r, the formula of the required 7π/4 is:
L=7π/4 *r;
2) according to the formula above:
L=7π*16/4=28π≈87,964594300514210676954014731826 (in).
The area of the rectangle:
A = Length x Width = JK x KL = 36 cm²
If JK ≥ 4 cm, we have to prove that KL ≤ 9 cm.
Answer:
Assume that a. KL > 9 cm.
Then the area of rectangle JKLM is greater than b. 36 cm²,
which contradicts the given information that c. side is at least 4 cm long.
So the assumption must be false. Therefore, d. KL ≤ 9 cm.