Work or energy spent=force times distance=25N*4m=100Nm
power=energy or work divided by time=100Nm/5s=20Nm/s
Answer:
459.6J
Explanation:
Given parameters:
Angle of pull = 40°
Force applied = 30N
Distance moved = 20m
Unknown:
Work done by Kraig = ?
Solution:
To solve this problem;
Work done = F x dcosФ
d is the distance
F is the force
Ф is the angle given
Work done = 30 x 20cos40° = 459.6J
Answer:
B. 4 m/s
Explanation:
v=d/t
Running for 300 m at 3 m/s takes 100 seconds and running at 300 m at 6 m/s takes 50 seconds. 100 s + 50 s = 150 s (total time). Total distance is 600 m, so 600 m/ 150 s = 4 m/s.
Find the velocity of the object after one second.
v = vo + at
v = (0 m/s) + (9.8 m/s^2)(1 s)
v = 9.8 m/s
Now, using that, you can find the displacement in that one second between 1 and 2.
d = vot + (1/2)at^2
d = (9.8 m/s)(1 s) + (1/2)(9.8 m/s^2)(1 s)^2
d = 14.7 m
m = mass of the birdcage = 22.5 kg
F = net force acting on birdcage to move it = 140 N
a = acceleration produced due to the force applied
a)
Using newton's second law
a = F/m
inserting the values
a = 140/22.5
a = 6.22 m/s²
b)
t = time of travel of crate = 10.5 s
v₀ = initial velocity of the crate = 0 m/s
X = displacement of the crate
displacement of the crate is given as
X = v₀ t + (0.5) a t²
X = 0 (10.5) + (0.5) (6.22) (10.5)²
X = 342.88 m
