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KatRina [158]
3 years ago
15

A 72.0-kg skydiver is falling at a terminal velocity of 79.0 m/s. Which equation should be used to calculate the diver’s kinetic

energy?
Physics
1 answer:
rodikova [14]3 years ago
4 0

Answer:

KE= 1/2 * mass * Velocity^2

Explanation:

1/2 * 72.0kg* 79^2 m/s = 224676 J

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kirill [66]
The answer is true.
All object at any temperature emit radiant energy.
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You weigh 730N. What would you weigh if the earth were six times as massive as it is and its radius were four times its present
Ber [7]

The new weight is 273.8 N

Explanation:

The weight of an object on Earth is given by

W=mg

where

m is the mass of the object

g is the acceleration of gravity

The acceleration of gravity at the Earth's surface can be rewritten as

g=\frac{GM}{R^2}

where

G is the gravitational constant

M is the Earth's mass

R is the Earth's radius

Substituting into the previous equation,

W=\frac{GMm}{R^2}

We said that in normal conditions, the weight of the person is 730 N:

W=\frac{GMm}{R^2}=730 N

Later, we are said that:

  • The mass of the Earth increases by a  factor of 6, M'=6M
  • The radius of the Earth increases by a factor of 4, R'=4R

Substituting into the equation, we find the new weight of the person in these conditions:

W'=\frac{G(6M)m}{(4R)^2}=\frac{6}{16}(\frac{GMm}{R^2})=\frac{3}{8}W

So, the new weight is 3/8 of the original weight, therefore:

W'=\frac{3}{8}(730)=273.8 N

Learn more about gravity:

brainly.com/question/1724648

brainly.com/question/12785992

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3 0
3 years ago
6.2 x 10^18 is equal to<br><br> A one ohm<br> B. one coulomb<br> C. one volt<br> D. one ampere
zhannawk [14.2K]
<h3>Answer:</h3><h3>B.one coulomb</h3>

<h3>Explanation:</h3><h3>It takes an enormous number of electrons to equal one coulomb.In fact,it takes about 6.2x10¹⁸.Looking at this from the opposite perspective,one electron has a negative charge equal to -1.6x10¹⁹ coulombs.</h3>

5 0
3 years ago
You have designed and constructed a solenoid to produce a magnetic field equal in magnitude to that of the Earth (5.0 10-5 T). I
saul85 [17]

Answer:

I = 0.03637 A

Explanation:

The given data in the question is

Magnetic field : B = 5.0 \times 10^{-5} T

Turns : N = 350

Length : L = 32 cm = 0.32 m

So, number of turns per unit length :

n=\frac{N}{L}

n=\frac{350\: turns}{0.32 m}

n=1093.75 \: turns \: per \: meter

If current is I , then magnetic field is given by

B = \mu_{0} \times n \times I

Also,

I = \frac{B}{\mu_{0} \times n}

Insert the values

I = \frac{5.0 \times 10^{-5}}{4 \pi \times 10^{-7} \times 1093.75} A

I = 0.03637 A

The current will be I = 0.03637 A

5 0
3 years ago
A gymnast practices two dismounts from the high bar on the uneven parallel bars. during one dismount, she swings up off the bar
mr_godi [17]
<span>The working formula to analyze this problem is Vf^2 - Vo^2 = 2gs where Vf = velocity at which the gymnast hits the ground Vo = initial velocity of the gymnast (given as 4 m/s and -3 m/s) g = acceleration due to gravity = 9.8 m/sec^2 (constant) s = height at which gymnast starts her dismount For the first dismount, Vf^2 - (4)^2 = 2(9.8)(s) Vf^2 = 16 + 19.6s and for the second dismount, Vf^2 - (-3)^2 = 2(9.8)(s) Vf^2 = 9 + 1.6s Since "s" is the same for both dismounts, then her final velocity in the first dismount is higher than that of her second dismount.</span>
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3 years ago
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