The question is incomplete, here is the complete question:
What volume (mL) of the partially neutralized stomach acid having concentration 2M was neutralized by 0.01 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)
<u>Answer:</u> The volume of HCl neutralized is 0.125 mL
<u>Explanation:</u>
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is HCl (Stomach acid)
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
Hence, the volume of HCl neutralized is 0.125 mL
The Fe charge is 2+ and the O charge is 2- so the ratio is 1:1
FeO
Answer:
Mixtures can be either homogeneous or heterogeneous. A mixture in which its constituents are distributed uniformly is called homogeneous mixture, such as salt in water. A mixture in which its constituents are not distributed uniformly is called heterogeneous mixture, such as sand in water.
An Ionic bond is the result of transfer of electrons between atoms
Answer is: volume of methane is 78.4 mL.
n(CH₄) = 0.0035 mol.
At standard pressure and temperature:
V(CH₄) = n(CH₄) · Vm
V(CH₄) = 0.0035 mol · 22.4 L/mol.
V(CH₄) = 0.0784 L · 1000 mL/L = 78.4 mL.
Vm - molar volume.
