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Elza [17]
3 years ago
9

BRAINLIEST AND 12POINTS

Biology
2 answers:
stealth61 [152]3 years ago
7 0
Q1:
Production of urea/conversion
of ammonia takes place in the live
Answer: (D)

Q2:
Let's start by process of elimination

the diaphragm contracts which helps you breathe

air pressure is pretty obvious

the intercostal muscles between your ribs also help enlarge the chest cavity as does the diaphragm

therefore the only thing that doesn't help is
D
Komok [63]3 years ago
6 0
1. Which structure of the excretory system in humans is responsible for converting ammonia into urea? - Liver is responsible for converting ammonia into urea.

2. Breathing in humans is driven by all of the following except
B. Air Pressure.

Hope I helped. Have a wonderful day.
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In garden peas, long stems are dominant to short stems, and yellow seeds are dominants to green seeds, too long/yellow pea plant
Lera25 [3.4K]

Answer:

A) 300

B) 3:1

C) 9 long yellow : 3 long green : 3 short yellow : 1 short green

Explanation:

Long stems (L_) are dominant to short stems (ll)

Yellow seeds (Y_) are dominant to green seeds (yy)

We interbred pea plants with long stems and yellow seeds (L_Y_), but they had a short green parent (llyy) that could have only produced <em>ly</em> gametes, so our plants are heterozygous <em>LlYy</em>.

C) We interbred them LlYy x LlYy. If the two genes are unlinked, this is a typical dihybrid cross and from Mendel's law of independent assortment we know that the offspring will have the following phenotypic ratios:

  • 9/16 L_Y_ (Long, yellow)
  • 3/16 L_yy (Long, green)
  • 3/16 llY_ (short, yellow)
  • 1/16 llyy (short, green)

A) 3/16 × 1600 = 300 plants will be long and green.

B)

9/16 + 3/16 = 12/16= 3/4 plants will be yellow;

3/16 + 1/16 = 4/16= 1/4 plants will be green.

The ratio will be 3 yellow : 1 green

6 0
3 years ago
__ refers to an inheritance pattern where there is more than one dominant allele that can be expressed at the same time.
Alchen [17]

Answer:

Codominance- its a relationship ebtween two versions of a gene. If both allels are domiant, it's called codominance.

Explanation:

5 0
3 years ago
A tricyclic antidepressant has been prescribed to a 77-year-old client whose current medication regimen includes omeprazole, cap
diamong [38]
<span>Monitor the client closely for bleeding and review coagulation indices when available.

</span>

Combining TCAs with warfarin creates a risk for bleeding, which should be addressed in the nursing care plan. There is no known interaction between TCAs and calcium supplements or bisphosphonates that would create a risk for hypocalcemia. TCAs do not heighten the risk of gastroesophageal reflux. TCAs can affect blood pressure, but this is unrelated to any known drug-drug interactions.

According to prep u/ Course point

3 0
3 years ago
Read 2 more answers
Why sex-linked traits appear more often in males than in females.
umka21 [38]
Because for female sex link desease would require X°X° but for male X°Y so during crossing X linked dear are more common in male.
7 0
3 years ago
Read 2 more answers
Suppose two independently assorting genes are involved in the pathway that determines fruit color in squash. These genes interac
makvit [3.9K]

Answer:

100% yellow fruit color, Yyww.

Explanation:

<u>Available data</u>:

  • two independently assorting genes
  • the W allele codes for a dominant white phenotype
  • w allele codes for a colored squash
  • The allele Y codes for a dominant yellow phenotype
  • the allele y codes for a recessive green phenotype
  • The phenotypes from the first locus will always mask the phenotype produced by the second locus if the dominant allele (W) is present at the first locus. This masking pattern is known as dominant epistasis

Epistasis means "interruption" and refers to interactions between genes located in different loci in the same chromosome. An “epistatic gene” can alter, influence, or suppress the expression of a "hypostatic gene". When the epistatic gene is dominant, the interaction is known as "dominant epistasis".

W suppresses the expression of Y and y, this means that whenever W is present, the fruit is white. If W <u>is not</u> present, the fruit color can be expressed.

So, the proposed cross in the present problem occurs between a green fruited individual and yellow fruited individual, which suggests that W is absent.

<em>Genotype for Green fruit: yyww</em>

<em>Genotype for purebred Yellow fruit: YYww</em>

Cross:

Parental) YYww    x    yyww

Gametes) Yw  Yw  Yw  Yw  yw  yw  yw  yw

Punnet square)    Yw       Yw       Yw      Yw

                 yw    Yyww  Yyww  Yyww  Yyww

                 yw    Yyww  Yyww  Yyww  Yyww

                 yw    Yyww  Yyww  Yyww  Yyww

                 yw    Yyww  Yyww  Yyww  Yyww

F1) 100% Yellow fruited plants, Yyww

As these two genes assort independently, we can also represent the cross for each gene by separate, like this:

For w gene:

Parental) ww  x  ww

Gametes) w w w w

Punnet square)  w     w

                 w     ww   ww

                 w      ww  ww

F1) 4/4 or 100% colored-fruits

For Y gene:

Parental) YY  x  yy

Gametes) Y Y y y

Punnet square)  Y     Y

                 y     Yy     Yy

                 y     Yy     Yy

F1) 4/4 or 100% yellow fruits, Yy.

3 0
3 years ago
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