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KatRina [158]
4 years ago
6

Predict the formula of the gas produced when sodium phosphide, Na3P(s), is treated with water.

Chemistry
2 answers:
xenn [34]4 years ago
6 0
The answer to your question is
PH3 (g)
Elanso [62]4 years ago
3 0

Answer:

The formula of the gas produced is PH_3.

Explanation:

Whenever metal phosphides reacts with water they form phosphine gas and alkaline solution of metal hydroxide.

M_3P_x(s)+3xH_2O(l)\rightarrow 3M(OH)_x(aq)+xPH_3(g)

So, when sodium phosphide is treated with water it gives phosphine gas and sodium hydroxide solution as a product.

Na_3P(s)+3H_2O(l)\rightarrow 3NaOH(aq)+PH_3(g)

The formula of the gas produced is PH_3.

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3 years ago
A solution of which of the following coordination compounds will form a precipitate when treated with aqueous AgNO3?
lidiya [134]

Answer:

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Explanation:

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If we consider the options carefully, only [Cr(NH3)6.]C13 possess counter ions outside the coordination sphere which can be precipitated when treated with aqueous AgNO3.

3 0
3 years ago
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Answer:

485.76 g of CO₂ can be made by this combustion

Explanation:

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If we only have the amount of butane, we assume the oxygen is the excess reagent.

Ratio is 2:8. Let's make a rule of three:

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Therefore, 2.76 moles of butane must produce (2.76 . 8)/ 2 = 11.04 moles of CO₂

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5 0
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I hope this helps in any way :)

4 0
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4 years ago
Read 2 more answers
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