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3 years ago

Predict the formula of the gas produced when sodium phosphide, Na3P(s), is treated with water.

Chemistry

2 answers:

xenn [34]3 years ago

6 0

The answer to your question is
PH3 (g)

Elanso [62]3 years ago

3 0

Answer:

The formula of the gas produced is $PH_3$ .

Explanation:

Whenever metal phosphides reacts with water they form phosphine gas and alkaline solution of metal hydroxide.

$M_3P_x(s)+3xH_2O(l)\rightarrow 3M(OH)_x(aq)+xPH_3(g)$

So, when sodium phosphide is treated with water it gives phosphine gas and sodium hydroxide solution as a product.

$Na_3P(s)+3H_2O(l)\rightarrow 3NaOH(aq)+PH_3(g)$

The formula of the gas produced is $PH_3$ .

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Explanation :

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This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

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As we are given :

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