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3 years ago

Predict the formula of the gas produced when sodium phosphide, Na3P(s), is treated with water.

Chemistry

2 answers:

xenn [34]3 years ago

6 0

The answer to your question is
PH3 (g)

Elanso [62]3 years ago

3 0

Answer:

The formula of the gas produced is $PH_3$ .

Explanation:

Whenever metal phosphides reacts with water they form phosphine gas and alkaline solution of metal hydroxide.

$M_3P_x(s)+3xH_2O(l)\rightarrow 3M(OH)_x(aq)+xPH_3(g)$

So, when sodium phosphide is treated with water it gives phosphine gas and sodium hydroxide solution as a product.

$Na_3P(s)+3H_2O(l)\rightarrow 3NaOH(aq)+PH_3(g)$

The formula of the gas produced is $PH_3$ .

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What is the hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4.

Maksim231197 [3]

The hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4 is 2.7.

pH= -log[H+] - (i)

10^-3=H2So4

H+= 2×10-3

here ,

h2so4 ——— 2[H+] + so4^2-

thus [H+]= 2*10^(-3) because hydrogen ion has two moles

pH= -log[H+]

pH= -log(2×10^-3)

pH= 3-log2

pH= 3-log2pH= 2.7

The pH is 2.7

PH is the degree of alkalinity and acidicity in a solution.

Therefore, The hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4 is 2.7

Learn more about pH from the link below.

https://brainly.in/question/9937410

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1 year ago

Calculate the molecular mass or formula mass in any of CH4 NO2 SO3 C6H6 Nal

Zielflug [23.3K]

Answer:

Ch4 Is an ion so the molecule yes 5

Explanation:

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2 years ago

A tank holds 6.90 m3 of water. What is the volume in ft3? (3.28 ft = 1 m, Remember significant figures, but this answer does not

AleksAgata [21]

Volume of tank = $6.9 m^{3}$ (given)

Since, $1 m = 3.28 ft$

So,

$1 m^{3} = 35.287 ft^{3}$

For $6.9 m^{3}$ :

$6.9\times 35.287 ft^{3} = 243.4803 ft^{3}$

The significant rule for multiplication, states that the number of significant figures in the answer obtained by multiplication is determined by the value with the lowest number of significant digits.

Since, the minimum number of decimal places in the above multiplication operation is 1 so, the final result must be upto 1 decimal place only.

$243.4803 ft^{3} \simeq 243.5 ft^{3}$

Hence, volume in $ft^{3}$ is 243.5.

5 1

2 years ago

Read 2 more answers

Answer and work for this problem

MArishka [77]

We can write the balanced equation for the synthesis reaction as
H2(g) + Cl2(g) → 2HCl(g)

We use the molar masses of hydrogen chloride gas HCl and hydrogen gas H2 to calculate for the mass of hydrogen gas H2 needed:
mass of H2 = 146.4 g HCl *(1 mol HCl / 36.46 g HCl) * (1 mol H2 / 2 mol HCl) *
(2.02 g H2 / 1 mol H2)
= 4.056 g H2

We also use the molar masses of hydrogen chloride gas HCl and chlorine gas CL2 to calculate for the mass of hydrogen gas H2:
mass of CL2 = 146.4 g HCl *(1 mol HCl / 36.46 g HCl) * (1 mol Cl2 / 2 mol HCl) *
(70.91 g Cl2 / 1 mol Cl2)
= 142.4 g Cl2

Therefore, we need 4.056 grams of hydrogen gas and 142.4 grams of chlorine gas to produce 146.4 grams of hydrogen chloride gas.

6 0

2 years ago

Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =

MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{c}$