1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KatRina [158]
4 years ago
6

Predict the formula of the gas produced when sodium phosphide, Na3P(s), is treated with water.

Chemistry
2 answers:
xenn [34]4 years ago
6 0
The answer to your question is
PH3 (g)
Elanso [62]4 years ago
3 0

Answer:

The formula of the gas produced is PH_3.

Explanation:

Whenever metal phosphides reacts with water they form phosphine gas and alkaline solution of metal hydroxide.

M_3P_x(s)+3xH_2O(l)\rightarrow 3M(OH)_x(aq)+xPH_3(g)

So, when sodium phosphide is treated with water it gives phosphine gas and sodium hydroxide solution as a product.

Na_3P(s)+3H_2O(l)\rightarrow 3NaOH(aq)+PH_3(g)

The formula of the gas produced is PH_3.

You might be interested in
25 points please help
maxonik [38]

Answer : Option (A) Accelerator 2 model has the lowest percentage of energy lost as waste.

Solution : Given,

For Accelerator 1 model,

Input energy = 2078.3 J

Wasted energy = 663.1 J

Output energy = 1415.2 J

For Accelerator 2 model,

Input energy = 7690.0 J

Wasted energy = 2337.5 J

Output energy = 5353.5 J

For Accelerator 3 model,

Input energy = 4061.9 J

Wasted energy = 2259.6 J

Output energy = 1802.3 J

Formula used for lowest percentage of energy lost as waste is:

% energy lost as waste = (Total energy wasted / Total input energy )  ×  100

For Accelerator 1 model,

% energy lost as waste = \frac{663.1}{2078.3}\times100 = 31.90%

For Accelerator 2 model,

% energy lost as waste = \frac{2337.5}{7690.0}\times100 = 30.39%

For Accelerator 3 model,

% energy lost as waste = \frac{2259.6}{4061.9}\times100 = 55.62%

So, we conclude that the Accelerator 2 model has the lowest percentage of energy lost as waste.



6 0
3 years ago
A mixture of helium and methane gases, at a total pressure of 821 mm Hg, contains 0.723 grams of helium and 3.43 grams of methan
Nookie1986 [14]

<u>Answer:</u>

<u>For 1:</u> The partial pressure of helium is 376 mmHg and that of methane gas is 445 mmHg

<u>For 2:</u> The mole fraction of nitrogen gas is 0.392 and that of carbon dioxide gas is 0.608

<u>Explanation:</u>

<u>For 1:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For helium:</u>

Given mass of helium = 0.723 g

Molar mass of helium = 4 g/mol

Putting values in equation 1, we get:

\text{Moles of helium}=\frac{0.723g}{4g/mol}=0.181mol

  • <u>For methane gas:</u>

Given mass of methane gas = 3.43 g

Molar mass of methane gas = 16 g/mol

Putting values in equation 1, we get:

\text{Moles of methane gas}=\frac{3.43g}{16g/mol}=0.214mol

To calculate the mole fraction , we use the equation:

\chi_A=\frac{n_A}{n_A+n_B}     .......(2)

To calculate the partial pressure of gas, we use the equation given by Raoult's law, which is:

p_{A}=p_T\times \chi_{A}       ......(3)

  • <u>For Helium gas:</u>

We are given:

n_{He}=0.181mol\\n_{CH_4}=0.214mol

Putting values in equation 2, we get:

\chi_{He}=\frac{0.181}{0.181+0.214}=0.458

Calculating the partial pressure by using equation 3, we get:

p_T=821mmHg\\\\\chi_{He}=0.458

Putting values in equation 3, we get:

p_{He}=0.458\times 821mmHg=376mmHg

  • <u>For Methane gas:</u>

We are given:

n_{He}=0.181mol\\n_{CH_4}=0.214mol

Putting values in equation 2, we get:

\chi_{CH_4}=\frac{0.214}{0.181+0.214}=0.542

Calculating the partial pressure by using equation 3, we get:

p_T=821mmHg\\\\\chi_{CH_4}=0.542

Putting values in equation 3, we get:

p_{CH_4}=0.542\times 821mmHg=445mmHg

Hence, the partial pressure of helium is 376 mmHg and that of methane gas is 445 mmHg

  • <u>For 2:</u>

We are given:

Partial pressure of nitrogen gas = 363 mmHg

Partial pressure of carbon dioxide gas = 564 mmHg

Total pressure = (363 + 564) mmHg = 927 mmHg

Calculating the mole fraction of the gases by using equation 3:

<u>For nitrogen gas:</u>

363=\chi_{N_2}\times 927\\\\\chi_{N_2}=\frac{363}{927}=0.392

<u>For carbon dioxide gas:</u>

564=\chi_{CO_2}\times 927\\\\\chi_{CO_2}=\frac{564}{927}=0.608

Hence, the mole fraction of nitrogen gas is 0.392 and that of carbon dioxide gas is 0.608

6 0
3 years ago
Match the vocabulary word with the defination.
OLga [1]

Answer:

1. d

2. b

3. d

4. e

5. a

explanation:

there's nothing else to explain

3 0
3 years ago
Read 2 more answers
Question is in picture
notsponge [240]

Answer:

Explanation: hELLO its b

6 0
3 years ago
What information about elements can be collected from the periodic table?
Lostsunrise [7]

Answer:

A lot

Explanation:

- As you go down a group, the elements get larger in size

- All of the elements of the same group have the same # of valence electrons

- As you go to the right of a period, the # of electrons in the outermost shell increases

- The elements at the top right of the table have the highest electronegativity

- Groups 13 through 17 are nonmetals

- The last group contains noble gases

etc.

8 0
3 years ago
Other questions:
  • What mass of NH4NO3 would you need to make 250.0mL of a 0.78M solution?
    6·2 answers
  • Calcium has an atomic number of 20 and 2 valence electrons. Oxygen has an atomic number of 8 and 6 valence electrons. Neon has a
    9·1 answer
  • Which reaction is most likely to have a positive ΔSsys?
    12·1 answer
  • How to determine reaction order in reactant?
    15·1 answer
  • Why do you think properties of materials used would be considered a constraint?
    5·1 answer
  • If Kc = 4.0×10−2 for PCl3(g)+Cl2(g)⇌PCl5(g) at 520 K , what is the value of Kp for this reaction at this temperature?
    15·1 answer
  • PLEASE HELPPPPPP<br> Which of the following statements is correct for the equation shown here?
    10·1 answer
  • A ball has a mass of 2.0 kg and travels a distance of 24 meters in 10 seconds what is the Velocity
    5·1 answer
  • you have a sample of.neon gas that you want to use to.make a glowing sign. you investigate that the gas sample is at 45c and has
    12·1 answer
  • Naming and Writing Formulas Assignment.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!