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TEA [102]
2 years ago
15

Which event is an example of a contact force?

Chemistry
1 answer:
Alborosie2 years ago
6 0

Answer: D. A person pulling a sled

Explanation:

A contact force is any force that requires contact/touch to occur, such as kicking, pulling, or pushing something.

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An object has a density of 10.00 g/mL. If the object has a volume of<br> 25.00 ml, what is the mass?
SVEN [57.7K]

Answer:

The answer is

<h2>250 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of object = 25 mL

Density = 10 g/mL

The mass of the object is

mass = 25 × 10

We have the final answer as

<h3>250 g</h3>

Hope this helps you

6 0
3 years ago
El agua con trozos de hielo es heterogenea o homogenea
dimaraw [331]
El agua con hielo es sistema heterogénea .
4 0
2 years ago
1. How do metals and non-metals react with acids? Write and explain the chemical equation for the reaction of magnesium with sul
Nata [24]

Answer:

1. How do metals and non-metals react with acids?

Ans : Non metals does not react with acids while metals react with acids and produce hydrogen gas that burns with a 'pop'sound.

2. Write and explain the chemical equation for the reaction of magnesium with sulphuric acid and aluminium with hydrochloric acid.

Magnesium + sulphuric acid = Hydrogen + salt

Mg(s) + H2SO4 (aq) MgSO 4(aq) +H2 (g)

Aluminium + Hydrochloric acid = Hydrogen + Aluminium chloride

2Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g)

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Answer:

hii

Explanation:

8 0
2 years ago
What volume will be occupied by 11.7 g of Helium in a balloon at an altitude of 10.0 km if the air pressure is 0.262 atm and the
matrenka [14]

Answer: 204 L

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 0.262 atm

V = Volume of gas = ?

n = number of moles = \frac{\text {given mass}}{\text {molar mass}}=\frac{11.7g}{4g/mol}=2.92

R = gas constant =0.0821Latm/Kmol

T =temperature =-50^0C=(273+(-50))K=223K

V=\frac{nRT}{P}

V=\frac{2.92\times 0.0820 L atm/K mol\times 223K}{0.262atm}=204L

Thus volume occupied by 11.7 g of Helium in a balloon is 204L

6 0
3 years ago
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