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artcher [175]
3 years ago
10

Someone please help me i’m stuck

Chemistry
1 answer:
Daniel [21]3 years ago
5 0
I thought about writing it for you but then i found this and thought i will give help but at the sometime allow you write the response you self

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What is the product of 1.65 and 1.05 x 10-27
lilavasa [31]

Answer:

-<em>9</em><em>.</em><em>6</em><em>7</em><em>5</em>

Explanation:

<em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>m</em><em>e</em><em> </em><em>i</em><em>f</em><em> </em><em>i</em><em>m</em><em> </em><em>w</em><em>r</em><em>o</em><em>n</em><em>g</em><em>.</em><em>!</em><em>!</em><em> </em><em />

3 0
3 years ago
Read 2 more answers
someone pls help me with my chemistry test plsss my teacher changes the questions so I can't search them up. its 21 questions so
shusha [124]

Answer:

Correct option is

B

5 liters of CH

4

(g)NO

2

at STP

No. of molecules=

22.4

5

mol=

22.4

5

×N

A

molecules

A) 5ℊ of H

2

(g)

No. of moles=

2

5

mol=

2

5

×N

A

molecules

B) 5l of CH

4

(g)

No. of moles of CH

4

=

22.4

5

mol=

22.4

5

N

A

molecules

C) 5 mol of O

2

=5N

A

O

2

molecules

D) 5×10

23

molecules of CO

2

(g)

Molecules of 5l NO

2

(g) at STP=5l of CH

4

(g) molecules at STP

Therefore, option B is correct.

7 0
2 years ago
How are energy and mass connected during the formation of an atom?
Jlenok [28]
I think the right answer for this question is option A. The energy absorbed so the mass will be increased. 
6 0
3 years ago
How many moles are in 15.5-g SiO2
DochEvi [55]

Answer:

0.26 moles

Explanation:

Number of moles = mass/molar mass

Mass of SiO2 = 15.5g

Molar mass of SiO2 = 60.08g/mol

Number of moles = 15.5g/60.08g/mol

=0.257

= 0.26 moles

8 0
3 years ago
Do you always have to begin with two compounds in a neutralization reaction
Paladinen [302]

Answer:

Yes.

Explanation:

Only an acidic compound and then a basic compound react(neutralization reaction) to give a salt.

Acid+Base=Salt+Water.

Hope this helps❤❤❤

3 0
3 years ago
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