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Delicious77 [7]
3 years ago
11

Pleaseee, PLEASEEEEEE I need HELPP with this

Chemistry
2 answers:
weqwewe [10]3 years ago
4 0

The pictures to the right show two samples of substance X. Answer the questions below about the intensive and extensive properties of substance X. You may assume that both cubes are solid (that is, not hollow inside).


Sample A melts at the same temperature as sample B.    

Sample B has a larger mass than sample A.

Sample A has a smaller volume than sample B.

If sample A floats in water, sample B . will also float in water

If sample B is attracted to a magnet, sample A will also be attracted to a magnet.

Savatey [412]3 years ago
3 0

Explanation:

Melting is defined as a change in which a solid changes into liquid state.

For example, an ice cube will melt at room temperature whereas a large ice block will also melt at room temperature.

Therefore, sample A melts at the same temperature as sample B.

Since sample A is small in size whereas sample B is larger in size. Hence, sample B has a larger mass than sample A. Also, sample A has smaller volume than sample B.

On the other hand, floating ability of a substance depends on its density. Therefore, being sample of same substance if sample A floats in water then sample B will also float in water.

Also, it is given that sample B is attracted to a magnet therefore, sample A will also be attracted to a magnet.

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rosijanka [135]

Answer:

A.The two ends are like poles

Explanation:

Magnets are composed of a north pole and a south pole. If two like poles of a magnetic are placed near each other, the two ends seem to push apart.

The reason for this is that, when like poles of two magnets are made to face each other, the lines of forces are in opposite directions, hence the magnets repel.

If unlike poles of two bar magnets are made to face each other, the magnetic lines of force are now in the same direction therefore the unlike poles attract each other.

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3 years ago
A helium-filled balloon at 310.0 K and 1 atm, contains 0.05 g He, and has a volume of 1.21 L. It is placed in a freezer (T = 235
trapecia [35]

Answer : The value of \Delta E of the gas is 2.79 Joules.

Explanation :

First we have to calculate the moles of helium.

\text{Moles of helium}=\frac{\text{Mass of helium}}{\text{Molar mass of helium}}

Molar mass of helium = 4 g/mole

\text{Moles of helium}=\frac{0.05g}{4g/mole}=0.0125mole

Now we have to calculate the heat.

Formula used :

q=nc_p\Delta T\\\\q=nc_p(T_2-T_1)

where,

q = heat

n = number of moles of helium gas = 0.0125 mole

c_p = specific heat of helium = 20.8 J/mol.K

T_1 = initial temperature = 310.0 K

T_2 = final temperature = 235.0 K

Now put all the given values in the above formula, we get:

q=nc_p(T_2-T_1)

q=(0.0125mole)\times (20.8J/mol.K)\times (235.0-310.0)K

q=-19.5J

Now we have top calculate the work done.

Formula used :

w=-p\Delta V\\\\w=-p(V_2-V_1)

where,

w = work done

p = pressure of the gas = 1 atm

V_1 = initial volume = 1.21 L

V_2 = final volume = 0.99 L

Now put all the given values in the above formula, we get:

w=-p(V_2-V_1)

w=-(1atm)\times (0.99-1.21)L

w=0.22L.artm=0.22\times 101.3J=22.29J

conversion used : (1 L.atm = 101.3 J)

Now we  have to calculate the value of \Delta E of the gas.

\Delta E=q+w

\Delta E=(-19.5J)+22.29J

\Delta E=2.79J

Therefore, the value of \Delta E of the gas is 2.79 Joules.

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