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Anastasy [175]
3 years ago
7

Which of the following is characterized by existing at a discrete energy level?

Chemistry
2 answers:
Bingel [31]3 years ago
8 0

Answer:

The correct option is: D) Subatomic Particle

Explanation:

Electrons are the negatively charged, stable sub-atomic particles that exist in <u>discrete energy levels, called the electron shells</u>, around the nucleus of an atom.

Each electronic shell consists of a fixed number of electrons and these electronic shells are denoted by the symbol K, L, M, N, and so on.

<u>Therefore, electron is the sub-atomic particle that exists at a discrete energy level.</u>

hichkok12 [17]3 years ago
5 0
Energy levels are considered orbitals.
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A chemical formula includes the symbols of the elements in the compound and subscripts that indicate
kramer

The subscripts indicate the number of atoms of the element immediately before it.

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2 years ago
Hess’s law
Delvig [45]

From the statement of Hess' law, the enthalpy of the reaction A---> C is +90 kJ

<h3>What is Hess' law?</h3>

Hess' law of constant heat summation states that for a multistep reaction, the standard enthalpy of reaction is always constant and is independent of the pathway or intermediate routes taken.

From Hess' law, the enthalpy change for the reaction A ----> C is calculated as follows:

A---> C = A ---> B + B ---> C

ΔH of A---> C = 30 kJ + 60 kJ

ΔH = 90 kJ

Therefore, the enthalpy of the reaction A---> C is +90 kJ

The above reaction A---> C can be shown in the enthalpy diagram below:

A -------------------> C (ΔH = +90 kJ)

\ /

\ / (ΔH = +60 kJ)

(ΔH = +30 J) \ /

> B

Learn more about enthalpy and Hess law at: brainly.com/question/9328637

8 0
2 years ago
Which is most complicated to separate?​
Sergio [31]

Answer: Atoms are the hardest substance to separate

7 0
2 years ago
Which of the following measurements contains 2 significant figures?
Trava [24]
The answer would be 371 because it has multiple complete digits
7 0
3 years ago
A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg
Brut [27]

Answer:  1.0\times 10^2g

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

K_f = freezing point constant = 3.96^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}

Weight of solvent (X)= 950 g = 0.95 kg  

Molar mass of non electrolyte (urea) = 60.06 g/mol

Mass of non electrolyte (urea) added = ?

7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}

x=1.0\times 10^2g

Thus 1.0\times 10^2g urea was dissolved.

8 0
3 years ago
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