Answer:
Explanation:
The mass percentages of chlorine and fluorine:
Given:
Mass of chlorine = 5.753g
Mass of fluorine = 9.248g
Find the total of the masses given:
Total mass = mass of chlorine + mass of fluorine = 5.753 + 9.248 = 15.001g
% of Cl = 
x 100
% of Cl = 
x 100 = 38.35%
% of F = 
x 100
% of F = 
x 100 = 61.65%
Molar mass Cu(OH)2 => 97.561 g/mol
Therefore:
1 mole Cu(OH)2 ------------ 97.561 g
? moles Cu(OH)2 ----------- 68 g
= 68 x 1 / 97.561
= 68 / 97.561
= 0.696 moles of Cu(OH)2
Answer:
8 liters of the first salt solution and 12 liters of the second salt solution is needed to get 20L of a solution that is 30% salt
Explanation:
Let x represent the liters of the first salt solution
Let y represent the liters of the second salt solution
x + y= 20......equation 1
x= 20-y
The first solution is 20% salt and the second solution is 45% salt
20/100x + 45/100 y= 30/100 × 20
0.2x + 0.45y= 0.3×20
0.2x + 0.45y= 6............equation 2
Substitute 20-y for x in equation 2
0.2(20-y) + 0.45y= 6
4-0.2y+ 0.45y= 6
4 + 0.25y= 6
0.25y= 6-4
0.25y= 2
y= 2/0.25
y= 8
Substitute y for 8 in equation 1
x + y= 20
x + 8=20
x= 20-8
x= 12
Hence 8 liters of the first salt solution and 12 liters of the second salt solution is needed to get 20L of a solution that is 30% salt.
Station model, a pattern of meteorological symbols that represents the wheater at a particular observing station
Answer:
Transition metals, alkali metals, alkaline earth metals Transition metals - Middle of the periodic chart, only average reactivity. alkali metals - As mentioned above, very reactive. Bad choice, going from lower reactivity to higher reactivity.
Hope this answer is right!
