Explanation:
1,a: I) group 2 = strontium
ii) chlorine
iii) nitrogen
B) i) strontium outer shell=2
ii)nitrogen:outer shell=5
iii) chlorine=7
C)metal
strontium
nickel
molybdenum
cesium
tin
non metal:..
chlorine
nitrogen
neon
Answer:
Explanation:1) ΔrH = 2mol·ΔfH(NO) - (ΔfH(O₂) + ΔfH(N₂)).
ΔrH = 2 mol · 90.3 kJ/mol - (0 kJ/mol + 0 kJ/mol).
ΔrH = 180.6 kJ.
2) ΔS = 2mol·ΔS(NO) - (ΔS(O₂) + ΔS(N₂)).
ΔS = 2mol · 210.65 J/mol·K - (1mol · 205 J/mol·K + 1 mol · 191.5 J/K·mol).
ΔS = 24.8 J/K.
3) ΔG = ΔH - TΔS.
55°C: ΔG = 180.6 kJ - 328.15 K · 24.8 J/K = 172.46 kJ.
2570°C: ΔG = 180.6 kJ - 2843.15 K · 24.8 J/K = 110.09 kJ.
3610°C: ΔG = 180.6 kJ - 3883.15 K · 24.8 J/K = 84.29 kJ.
Answer: 1.80g
Explanation:
Molar Mass of AlCl3 = 27 + (3x35.5)
= 27 + 106.5 = 133.5g/mol
Number of mole of AlCl3 = 0.0135mol
Mass = 0.0135 x 133.5= 1.80g
Since you did not give a calculation,
I will just give an example. Suppose that you are to burn 5 kg of methane (CH4)
from 0 to 10°C. The specific heat capacity of methane is 4.475 kJ/kg-K.
H
= mCpT
H
= (5kg)( 4.475 kJ/kg-K)(10-0)
H = 223.75 kJ
Because the enthalpy is positive
in value, methane takes in heat.
Answer:
1. 0.45 mole
2. 49.95g
Explanation:
The following were obtained from the question:
Volume of solution = 300mL = 300/1000 = 0.3L
Molarity = 1.5 M
Mole of CaCl2 =?
1. We can obtain the mole of the solute as follow:
Molarity = mole of solute /Volume of solution
1.5 = mole of solute/0.3
Mole of solute = 1.5 x 0.3
Mole of solute = 0.45 mole
2. The grams in 0.45 mole of CaCl2 can be obtained as follow:
Molar Mass of CaCl2 = 40 + (35.5 x 2) = 40 + 71 = 111g/mol
Mole of CaCl2 = 0.45 mole
Mass of CaCl2 =?
Mass = number of mole x molar Mass
Mass of CaCl2 = 0.45 x 111
Mass of CaCl2 = 49.95g
