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2 years ago

If a sample of 0.362 m lithium phosphate contains 0.284 g of lithium, what is the volume of the sample?

Chemistry

2 answers:

Leni [432]2 years ago

7 0

Answer;

= 0.03791 Liters

Solution and explanation;

-The molar mass of Li3PO4 is 115.79 g/mol.

-If lithium is 6.9 g/mol, multiplied by 3 (from Li3PO4), that would be 20.7 g/mol.

-Now we can use this to find the percentage of Li in Li3PO4, 20.7/115.79 = 0.1788 or 17.88%

-This 17.88% can tell us the mass of Li3PO4 using the mass which 0.284. Now lets divide 0.284 by 0.1788 = 1.589 g. This now the mass of Li3PO4.

-Using that, we can now easily find the moles of Li3PO4,

using the molar mass. So (1.589g)(1mol/115.79g)=0.013723 moles of Li3PO4.

-From this, we can now find the volume using molarity (0.362), which is moles per Liter.

= (0.013723 moles)(1L/0.362mol)=0.03791 L

fenix001 [56]2 years ago

3 0

From the periodic table:
mass of lithium = 6.941 grams
number of moles = mass / molar mass
number of moles of Li = 0.284 / 6.941 = 0.0409 moles

Molarity can be calculated using the following rule:
molarity = number of moles of solute / liters of solution
volume (in liters) = number of moles of solute / molarity
volume = 0.0409 / 0.362 = 0.1129 liters

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Answer:

Scheme is Attached.

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2 years ago

0.352 g sample of a diprotic acid is dissolved in water and titrated with 0.150 M NaOH.0.150 M NaOH. What is the molar mass of t

Aliun [14]

<h3>Answer:</h3>

128.94 g/mol

<h3>Explanation:</h3>

Given;

Mass of diprotic acid, H₂X =0.352 g

Molarity of NaOH = 0.150 M

Volume of the NaOH = 36.4 mL

We are required to calculate the molar mass of the acid.

Note: A diprotic acid is an acid that contains 2 replaceable hydrogen atoms

<h3>Step 1: Write the balanced equation fro the reaction;</h3>

The balanced equation for the reaction between the diprotic acid and NaOH will be;

H₂X(aq) + 2NaOH(aq) → Na₂X(aq) + 2H₂O(l)

<h3>Step 2: Determine the number of moles of NaOH used </h3>

Given the molarity and volume of NaOH we can calculate the number of moles;

Moles of NaOH = Molarity × Volume

= 0.150 M × 0.0364 L

= 0.00546 moles

<h3>Step 3: Use the mole ratio to determine moles of the acid </h3>

From the equation;

1 mole of the acid reacts with 2 moles of NaOH

Therefore; H₂x : NaOH = 1 : 2

Moles of H₂x = 0.00546 moles ÷ 2

= 0.00273 moles

<h3>Step 4: Determine the molar mass of the acid.</h3>

Molar mass is the mass equivalent to 1 mole of a compound or element

From our calculations;

0.00273 moles = 0.352 g of the acid;

Therefore, mass in 1 mole ;

= 0.352 g ÷ 0.00273 moles

= 128.94 g/mol

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2 years ago

White phosphorus melts and then vaporizes at high temperatures. The gas effuses at a rate that is 0.404 times that of neon in th

Soloha48 [4]

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Explanation:

Ar=30,97g/mol

$R_{Px$ / $R_Ne}$ = $\sqrt{Mr(Ne)/Mr(Px)}$ =0,404

0,404= $\sqrt{20,18/30,97*x}$

$0,404^{2}$ =20,18/30,97*x

X=20,18/30,97*0,163

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2 years ago

A 111.6 gram sample of iron (MW=55.8) was heated from 0 degrees C to 20 degrees C. It absorbed 1004 Joules of energy. What is th

qwelly [4]

Use the equation q=ncΔT.
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c=molar heat capacity
ΔT=change in temperature (in this case 20°C)
You have to rewrite the equation for c.
c=q/nΔT
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c=24.1 J/mol°C

I hope this helps

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2 years ago

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Luden [163]

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2 years ago