Answer;
= 0.03791 Liters
Solution and explanation;
-The molar mass of Li3PO4 is 115.79 g/mol.
-If lithium is 6.9 g/mol, multiplied by 3 (from Li3PO4), that would be 20.7 g/mol.
-Now we can use this to find the percentage of Li in Li3PO4, 20.7/115.79 = 0.1788 or 17.88%
-This 17.88% can tell us the mass of Li3PO4 using the mass which 0.284. Now lets divide 0.284 by 0.1788 = 1.589 g. This now the mass of Li3PO4.
-Using that, we can now easily find the moles of Li3PO4,
using the molar mass. So (1.589g)(1mol/115.79g)=0.013723 moles of Li3PO4.
-From this, we can now find the volume using molarity (0.362), which is moles per Liter.
= (0.013723 moles)(1L/0.362mol)=0.03791 L