Taking into account definition of percent yield, the percent yield for the reaction is 76.25%.
<h3>Percent yield</h3>
The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.
The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:
where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.
<h3>Percent yield in this case</h3>
In this case, you know:
- actual yield= 1.22 mol
- theorical yield= 1.60 mol
Replacing in the definition of percent yields:
Solving:
<u><em>percent yield= 76.25%</em></u>
Finally, the percent yield for the reaction is 76.25%.
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Answer:
A weak acid
Explanation:
Im not sure if its right. But lets see someone else do it.
Answer:
No. If you were to set up what the friend said it would look like this:
19.7g × 
==> 
×
The above does not look right because the grams do not cancel out. If it's not cancelled, it would be included in your final answer, but you're looking for moles not grams.
When setting up a stoichiometry equation, you have to put the same unit of measurement (ex- grams, cm, mm, etc.) on the numerator of one side and the denominator of the other side.
This would cancel out the unit.
For example: If you wanted to find out how much of 320 cm are in a meter.
*there are 100 cm in 1 meter*
(1. always start with the given number!)
(2. set up the next fraction where you can cancel out cm)
× 
= 3.2 m
Going back, your friend would have to switch the units from grams/moles to moles/grams. It would cancel out grams, which would leave moles. Therefore, moles will be included in your final answer.
× 
= _?_ moles
<span>The old car left on the side of the road showed signs of corrosion. We call this common chemical reaction rusting. The equation for this reaction can be written as 4Fe + 3O2 → 2Fe2O3. What are the reactants in the rusting process?
</span>
C. Iron and Oxygen
