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Sauron [17]
3 years ago
6

5. Can someone explain how to solve this?

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0

Answer:

AC = 5 cm

BD = 12.5 cm (3 sf) [or 2 × root 39]

BE = 6.93 cm (3 sf) [or 4 × root 3]

Step-by-step explanation:

CE = 8cm [CE is radius of circle]

AC + 3 = 8

<u>A</u><u>C</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>c</u><u>m</u>

BC = 8cm [BC is a radius of circle]

(AC)^2 + (AB)^2 = (BC)^2 [Pythagoras theorem]

25 + (AB)^2 = 64

AB = 6.2450 cm (5 sf) [or root 39]

BD = 2(BA)

= 2(6.2450)

<u>B</u><u>D</u><u> </u><u>=</u><u> </u><u>1</u><u>2</u><u>.</u><u>5</u><u> </u><u>c</u><u>m</u><u> </u><u>(</u><u>3</u><u> </u><u>s</u><u>f</u><u>)</u><u> </u><u>[</u><u>o</u><u>r</u><u> </u><u>2</u><u> </u><u>×</u><u> </u><u>r</u><u>o</u><u>o</u><u>t</u><u> </u><u>3</u><u>9</u><u>]</u>

(BA)^2 + (AE)^2 = (BE)^2 [Pythagoras theorem]

39 + 9 = (BE)^2

<u>B</u><u>E</u><u> </u><u>=</u><u> </u><u>6</u><u>.</u><u>9</u><u>3</u><u> </u><u>c</u><u>m</u><u> </u><u>(</u><u>3</u><u> </u><u>s</u><u>f</u><u>)</u><u> </u><u>[</u><u>o</u><u>r</u><u> </u><u>4</u><u> </u><u>×</u><u> </u><u>r</u><u>o</u><u>o</u><u>t</u><u> </u><u>3</u><u>]</u>

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