Answer:
The volume of the gas sample at standard pressure is <u>819.5ml</u>
Explanation:
Solution Given:
let volume be V and temperature be T and pressure be P.
1 torr= 1 mmhg
42.2 torr=42.2 mmhg
so,
Now
firstly we need to find the pressure due to gas along by subtracting the vapor pressure of water.
=735-42.2=692.8 mmhg
Now
By using combined gas law equation:
Here 
are standard pressure and temperature respectively.
we have
Substituting value, we get
Answer:
its absorbed by heat from consumers
Use the formula
E=mc^2
plug the values,
The amount of mass in kilograms would be lost is 8.71 x 10^-10
Assuming that you’re looking for the concentration of water in the solution, then it would be 0.028 M.
You would have to use the formula:
c1v1 = c2v2, where c =concentration and
v = volume
C1 = ?
V1 = 250 mL
C2 = 0.2 M
V2 = 35 mL
C1 x 250 mL = 0.2 M x 35 mL
C1 = (0.2 M x 35 mL) / 250 mL
C1 = 0.028 M of water added to 35mL of 0.2M HCl
Therefore, there is 0.028 M of water added to 35mL of 0.2M HCl
