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Aneli [31]
3 years ago
14

A probe from earth, with a mass of 106 kg, is in orbit around planet Pud in another solar system. Pud has a radius of 106 m and

the probe has an orbital radius of 107 m (its orbit is circular). If the speed of the probe in orbit is 1 km/s, what is the acceleration due to g
Physics
1 answer:
Ksju [112]3 years ago
4 0

Answer:

The acceleration due to gravity in planet Pud is of 9345.7m/s²

Explanation:

Since the probe is describing a circular motion around planet Pud, its centripetal acceleration is given by the formula:

a_c=\frac{v^{2}}{R}

Assuming there is no other external forces acting on the probe in the centripetal direction, we have that

a_c=g_{Pud}=\frac{v^{2}}{R}

Before we plug in the values, we have to convert the speed from km/s to m/s:

1\frac{km}{s} =1000\frac{m}{s}

Finally, using the given values, we can compute g_{Pud}:

g_{Pud}=\frac{(1000\frac{m}{s}) ^{2} }{107m}= 9345.7\frac{m}{s^{2}}

In words, the acceleration due to gravity in planet Pud is of 9345.7m/s²

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Answer:

See the answers below.

Explanation:

We will solve this problem by calculating each part separately.

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