Hello!
Answer: 7918 J
Explanation:
We are assuming that the floor (field) is completely horizontal since there's no information about that in the statement.
We are going to use the following formula:

Where:

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º

Then, by substituting we have:

acceleration = Velocity changes ÷ time of the velocity changes
4 m/s^2 =
4 × 10^(-3) × 3600 km / h =
4 × 3.6 =
14.4 km / h
Thus :
14.4 = V(2) - V(1) / t(2) - t(1)
14.4 = V(2) - 20 / 10
Multiply both sides by 10
10 × 14.4 = 10 × ( V(2) - 20 ) / 10
144 = V(2) - 20
Add both sides 20
144 + 20 = V(2) - 20 + 20
V(2) = 164 Km/h
Thus the final velocity after 10 seconds is 164 Km/h .
Rocket fuel will and smoke will emit from the thrusters.
60 days, tell me if I'm correct please.