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ASHA 777 [7]
3 years ago
11

A passenger jet flying at cruising altitude is often traveling in the upper troposphere at approximately 725 km per hour (or 450

mph). Why don't passenger jets burn up as meteors do?
Physics
1 answer:
kobusy [5.1K]3 years ago
7 0

Explanation:

Objects like meteors travel at high rates of the speed and thus, possess large amounts of the kinetic energy.  As the meteors enter Mesosphere, they enter more dense segment of earth's atmosphere with the greater numbers of the gas molecules.  Meteors which encounter the large numbers of the gas molecules at the high rates of the speed and generate large amounts of the friction in process. As a result, enormous heat is built up. This build-up of heat  ultimately causes the fast-traveling meteors to burn up in atmosphere.

<u>While passenger jets travel at very small speed as compared with the speed of the meteors and don not burn. </u>

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A projectile is fired with an initial speed of 40 m/s at an angle of elevation of 30∘. Find the following: (Assume air resistanc
BabaBlast [244]

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a. 2.0secs

b. 20.4m

c. 4.0secs

d. 141.2m

e. 40m/s, ∅= -30°

Explanation:

The following Data are giving

Initial speed U=40m/s

angle of elevation,∅=30°

a. the expression for the time to attain the maximum height is expressed as

t=\frac{usin\alpha }{g}

where g is the acceleration due to gravity, and the value is 9.81m/s if we substitute values we arrive at

t=40sin30/9.81\\t=2.0secs

b. the expression for the maximum height is expressed as

H=\frac{u^{2}sin^{2}\alpha  }{2g} \\H=\frac{40^{2}0.25 }{2*9.81} \\H=20.4m

c. The time to hit the ground is the total time of flight which is twice the time to reach the maximum height ,

Hence T=2t

T=2*2.0

T=4.0secs

d. The range of the projectile is expressed as

R=\frac{U^{2}sin2\alpha}{g}\\R=\frac{40^{2}sin60}{9.81}\\R=141.2m

e. The landing speed is the same as the initial projected speed but in opposite direction

Hence the landing speed is 40m/s at angle of -30°

3 0
3 years ago
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