Answer:
Replace the 4 with a 3 to make the equation true
Yes, I will list acute first (<90) and obtuse second (>90) and they need to add to 180
10 and 170
20 and 160
30 and 150
40 and 140
50 and 130
60 and 120
70 and 110
80 and 100 and so on
Answer:
X=14
Y=11
Step-by-step explanation:
14-11=3
14x2=28
11x2=22
22+28=50
Hope that works :)
Answer:
3/5
Step-by-step explanation:
sinA = opp/hyp
= 21/35
= 3/5
Since there are more parakeets than canaries, it is not possible to have only 1 of each bird in each cage <u>and</u> have the same number of birds in each cage.
He could use 42 cages, putting a canary in with the parakeet in 18 of them. Then he would have 18 cages with 2 birds each, and 24 cages with 1 bird each.
The only way to have the same number of birds (1) in all cages is to have 60 cages, 42 of which have 1 parakeet, and 18 of which have 1 canary.
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If more than 1 of each kind of bird can be put in the cage, the collection of birds could be put into 6 cages, each of which would be home to 7 parakeets and 3 canaries.
