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Ymorist [56]
3 years ago
15

A testable idea or explanation that leads to a scientific investigation is called a what

Physics
2 answers:
miss Akunina [59]3 years ago
7 0
<span>A testable idea or explanation that leads to a scientific investigation is called a hypothesis.</span>
Zina [86]3 years ago
3 0
The answer is Hypothesis.
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Two identical loudspeakers are placed on a wall 1.00 m apart. A listener stands 4.00 m from the wall directly in front of one of
natita [175]

Answer:

The phase difference is 0.659 rad.

Explanation:

Given that,

Distance between two identical loudspeakers d= 1.00  m

Distance between speakers and listener r= 4.00 m

Frequency = 300 Hz

Suppose we need to find the phase difference in radian between the waves from the speakers when they reach the observer

We need to calculate the r'

Using Pythagorean theorem

r'=\sqrt{d^2+r^2}

Where, d = distance between two identical loudspeakers

r = distance between speakers and listener

Put the value into the formula

r'=\sqrt{(1.00)^2+(4.00)^2}

r'=\sqrt{1.00+16.00}

r'=4.12\ m

We need to calculate the path difference

Using formula of path difference

|r'-r|=4.12-4.00

|r'-r|=0.12\ m

We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{v}{f}

Where, v = speed of sound

f = frequency

Put the value into the formula

\lambda=\dfrac{343}{300}

\lambda=1.143\ m

We need to calculate the phase difference

Using formula of phase difference

\phi=\dfrac{2\pi\times|r'-r| }{\lambda}

\phi=\dfrac{2\pi\times0.12}{1.143}

\phi=0.659\ rad

Hence, The phase difference is 0.659 rad.

7 0
4 years ago
What are the different ways that the simulation shows you that the equation is balanced, visually? For each balanced reaction, i
Nastasia [14]

Answer:

e

Explanation:

e

3 0
3 years ago
How will the frequency of a wave appear to change if the source of the wave is moving toward an observer
amm1812

pitch goes up on approach ... Doppler effect

6 0
3 years ago
Read 2 more answers
What is the bouncing of light when it changes media
matrenka [14]

When light passes from one medium to another, part of it continues on
into the new medium, while the rest of it bounces away from the boundary,
back into the first medium.

The part of the light that continues on into the new medium is <em>transmitted</em>
light.  Its forward progress at any point in its journey is <em>transmission</em>. 

Its direction usually changes as it crosses the boundary.  The bending is <em>
refraction</em>
.

The part of the light that bounces away from the boundary and heads back
into the first medium is <em>reflected</em> light.  The process of bouncing is <em>reflection</em>.


5 0
3 years ago
A potential energy function is given by u(x)=(3.00n)xâ(1.00n/m2)x3. at what position or positions is the force equal to zero?
qwelly [4]

I believe the correct form of the energy function is:

u (x) = (3.00 N) x + (1.00 N / m^2) x^3

or in simpler terms without the units:

u (x) = 3 x + x^3

Since the highest degree is power of 3, therefore there are two roots or solutions of the equation.

 

Since we are to find for the positions x in which the force equal to zero, u (x) = 0, therefore:

3 x + x^3 = u (x)

3 x + x^3 = 0

Taking out x:

x (3 + x^2) = 0

So one of the factors is x = 0.

 

Finding for the other two factors, we divide the two sides by x and giving us:

x^2 + 3 = 0

x^2 = - 3

x = sqrt (- 3)

x = - 1.732 i, 1.732 i

 

The other two roots are imaginary therefore the force is only equal to zero when the position is also zero.

 

Answer:

x = 0

5 0
4 years ago
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