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3 years ago

Hell Im Fatima berry i need help PLZZ

Physics

1 answer:

irinina [24]3 years ago

7 0

Answer:

static, sliding, rolling, and fluid friction

Explanation:

Static friction acts on objects when they are resting on a surface. For example, if you are hiking in the woods, there is static friction between your shoes and the trail each time you put down your foot

Sliding friction is friction that acts on objects when they are sliding over a surface. For example, you use sliding friction when you write with a pencil. The pencil “lead” slides easily over the paper, but there's just enough friction between the pencil and paper to leave a mark.

Rolling friction is friction that acts on objects when they are rolling over a surface. For example, this explains why most forms of ground transportation use wheels, including bicycles, cars, 4-wheelers, roller skates, scooters, and skateboards.

Fluid friction is friction that acts on objects that are moving through a fluid. For example, the air resistance on a skydiver

You might be interested in

What is the term of movement in a particular direction

Art [367]

That is a vector. It is a combination of direction and velocity. (You can think of Vector from Despicable Me to help you remember the term)
:)

7 0

3 years ago

After an eye examination, you put some eyedrops on your sensitive eyes. The cornea (the front part of the eye) has an index of r

mina [271]

Answer:

t = 103.45 n m

Explanation:

given,

refractive index of cornea = 1.38

refractive index of eye drop = 1.45

wavelength of refractive index = 600 nm

refractive index of eye drop is greater than refractive index of cornea and the air.

Formula used in this case

for constructive interference

$2 n t = (m + \dfrac{1}{2})\lambda$

At m = 0 for the minimum thickness, so

$2\times 1.45 \times t = (0 + 0.5)\times 600$

$2.9 \times t =300$

$t =\dfrac{300}{2.9}$

t = 103.45 n m

the minimum thickness of the film of eyedrops t = 103.45 n m

6 0

3 years ago

A woman falls to the ground while wearing a parachute. The air resistance on the parachute of the parachute is 500N. If the woma

scoundrel [369]

The gravitational force on the woman is A) 500 N

Explanation:

There are two forces acting on the woman during her fall:

The force of gravity, $F_G$ , acting downward
The air resistance, $F_D$ , acting upward

According to Newton's second law, the net force acting on the woman is equal to the product between the woman's mass and her acceleration:

$\sum F=ma$

where m is the mass of the woman and a her acceleration.

The net force can be written as

$\sum F = F_G - F_D$

Also, we know that the woman falls at a constant velocity (5 m/s), this means that her acceleration is zero:

$a=0$

Combining the equations together, we get:

$F_G-F_D = 0$

which means that the magnitude of the gravitational force is equal to the magnitude of the air resistance:

$F_G=F_D=500 N$

Learn more about forces and Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

5 0

3 years ago

Read 2 more answers

2..Read the following statements carefully and choose the correct option

Softa [21]

Answer:

statement 1 is correct

2 not sure

Explanation:

6 0

3 years ago

A kangaroo jumps straight up to a vertical height of 1.45 m. How long was it in the air before returning to Earth?

dexar [7]

Answer:

1.08 s

Explanation:

From the question given above, the following data were obtained:

Height (h) reached = 1.45 m

Time of flight (T) =?

Next, we shall determine the time taken for the kangaroo to return from the height of 1.45 m. This can be obtained as follow:

Height (h) = 1.45 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

1.45 = ½ × 9.8 × t²

1.45 = 4.9 × t²

Divide both side by 4.9

t² = 1.45/4.9

Take the square root of both side

t = √(1.45/4.9)

t = 0.54 s

Note: the time taken to fall from the height(1.45m) is the same as the time taken for the kangaroo to get to the height(1.45 m).

Finally, we shall determine the total time spent by the kangaroo before returning to the earth. This can be obtained as follow:

Time (t) taken to reach the height = 0.54 s

Time of flight (T) =?

T = 2t

T = 2 × 0.54

T = 1.08 s

Therefore, it will take the kangaroo 1.08 s to return to the earth.

3 0

3 years ago