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bixtya [17]
2 years ago
14

Robin is standing terrified at the end of a diving board, which is high above the water. If Robin has a mass of 76 kg and is sta

nding 1.6 m from the board's pivot point, what torque is Robin exerting on the board
Physics
1 answer:
masya89 [10]2 years ago
5 0

Answer:

 Torque = 1191.68 N-m

Explanation:

Given data

mass m = 76 kg

standingdistance r  = 1.6 m

Solution

we get here torque  that si express as

torque  = force × distance ................1

torque  = r × F sin(theta)

and we know that

F = mg   .........2

and g = 9.8 m/s²

put here value in equation 1 we get

Torque = 76 × 1.6 × 9.8 × sin(90)

 Torque = 1191.68 N-m

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Answer:

Comparison Microscope

Explanation:

The Comparison Microscope allows for comparison between two objects or samples by placing them side by side.

It is primarily used in criminology for ballistics which makes it ideal to find out if bullets, shells, or cartridge cases were fired from a specific weapon.

7 0
2 years ago
Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.59 times a second. A tack is stuck in the tire a
Vesna [10]

Answer:

Tangential speed=5.4 m/s

Radial acceleration=88.6m/s^2

Explanation:

We are given that

Angular speed=2.59 rev/s

We know that

1 revolution=2\pi rad

2.59 rev=2\pi\times 2.59=5.18\pi=5.18\times 3.14=16.27 rad/s

By using \pi=3.14

Angular velocity=\omega=16.27rad/s

Distance from axis=r=0.329 m

Tangential speed=r\omega=16.27\times 0.329=5.4m/s

Radial acceleration=\frac{v^2}{r}

Radial acceleration=\frac{(5.4)^2}{0.329}=88.6m/s^2

6 0
3 years ago
Which of the following would add more resistance? Check all that apply.
Blababa [14]

Answer:C. E.

Explanation:

4 0
2 years ago
g A ping pong ball (thin shell sphere) rolls down an incline at 30° from rest. What is its acceleration
Aleonysh [2.5K]

Answer:

Explanation:

According to newtons second law of motion;

F = ma .... 1

Also the force acting aong the inclines is expressed as;

F = mgsintheta

m is the mass of the object

a is the acceleration

theta is angle of inclination

Equate 1 and 2

ma = mg sin theta

a = gsin(theta)

a = 9.8sin30

a = 9.8(0.5)

a = 4.9m/s²

Hence the acceleration of the ping pong is 4.9m/s²

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Distinguish between speed and velocity?<br>atleast 4 point should write​
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mark me as brainliest ❤️

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