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bazaltina [42]
3 years ago
6

What magnitude charge creates a 1.0 n/c electric field at a point 1.0 m away?

Physics
1 answer:
Stolb23 [73]3 years ago
8 0

Answer:

1.1\cdot 10^{-10}C

Explanation:

The electric field produced by a single point charge is given by:

E=k\frac{q}{r^2}

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge

In this problem, we have

E = 1.0 N/C (magnitude of the electric field)

r = 1.0 m (distance from the charge)

Solving the equation for q, we find the charge:

q=\frac{Er^2}{k}=\frac{(1.0 N/c)(1.0 m)^2}{9\cdot 10^9 Nm^2c^{-2}}=1.1\cdot 10^{-10}C

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PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!
Montano1993 [528]

They literally gave you the answer but okay.

Correct answer should be: B. 490 Meters

1/2 x 9.8 x 10^2

Plug them in a calculator and you get <u>490 meters. </u>

<u>G </u>= Gravity which is 9.8 m/s^2

<u>T</u>= Time

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Read 2 more answers
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