Answer:
The speed of sound, in m/s, through air at this temperature is 343.5 m/s
Explanation:
Given;
distance traveled by sound, d = 1,687.5 meters
time taken for the sound to travel, t = 5 seconds
air temperature, θ = 10°C
Speed of sound = distance traveled by sound / time taken for the sound to travel
Speed of sound = d / t
= 1687.5 m / 5 s
= 337.5 m/s
Speed of sound at the given temperature is calculated as;
c = 337.5 + 0.6θ
c = 337.5 + 0.6 x 10
c = 337.5 + 6
c = 343.5 m/s
Therefore, the speed of sound, in m/s, through air at this temperature is 343.5 m/s
Answer:
v = 5.42 m/s
Explanation:
given,
height of the jumper = 1.5 m
velocity of sprinter = ?
kinetic energy can be transformed into potential energy
v = 5.42 m/s
Speed of the sprinter is equal to v = 5.42 m/s
Answer:
<h2>9.8 m/s²</h2>
Explanation:
<h2>Since the ball rises for 2.5 s, the time to fall is 2.5 s. The acceleration is 9.8 m/s2 everywhere, even when the velocity is zero at the top of the path. Although the velocity is zero at the top, it is changing at the rate of 9.8 m/s² downward.</h2>
Answer:
I just noticd i dont speak this launguage
Explanation:
