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Diano4ka-milaya [45]
3 years ago
7

A car speeds up while the engine delivers constant power. Is the acceleration greater at the beginning of this process or at the

end? Explain.
Physics
1 answer:
dsp733 years ago
4 0

Answer:

The acceleration greater at the beginning of this process

Explanation:

The car when starting to move is necessary an acceleration therefore at the beginning of the movement there is an acceleration. The engine power is at a constant value so that when the car reaches the maximum speed (constant speed) at that power there will be no acceleration.

That is to say, at constant speed = zero acceleration

And of course this final null acceleration will be less than the initial acceleration so that the car starts to move .

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A ship leaves a port at noon and travels due west at 20 knots. At 6 PM, a second ship leaves the same port and travels northwest
Amanda [17]

Answer:

v = 12.44 Knots

Explanation:

First ship starts at Noon with speed 20 Knots towards West

now we know that 2nd ship starts at 6 PM with speed 15 Knots towards North West

so after time "t" of 2nd ship motion the two ships positions are given as

r_1 = 20(t + 6)\hat i

r_2 = 15(t)(cos45\hat i + sin45\hat j)

now we can find the distance between two ships as

x = \sqrt{(20(t + 6) - 10.6 t)^2 + (10.6t)^2}

now we have

x^2 = (120 + 9.4 t)^2 + (10.6 t)^2

x^2 = 200.72 t^2 + 14400 + 2256 t

now we will differentiate it with respect to time

2x\frac{dx}{dt} = 401.44 t + 2256

here we know that

t = \frac{90}{15} = 6 hours

so we have

x = 187.5

now we have

2(187.5) v = 401.44(6) + 2256

v = 12.44 Knots

5 0
3 years ago
Calculate the force of gravity on the 1.2-kg mass if it were 1.9×107 m above earth's surface (that is, if it were four earth rad
Anettt [7]

Answer:

Force of gravity, F = 0.74 N

Mass of an object, m = 1.2 kg

Distance above earth's surface, d=1.9\times 10^7\ m

Mass of Earth, M=5.97\times 10^{24}\ kg

Radius of Earth, r=6.37\times 10^6\ m

We need to find the force of gravity above the surface of Earth. It is given by :

F=G\dfrac{mM}{R^2}

R = r + d

R = 25370000 m

F=6.67\times 10^{-11}\times \dfrac{5.97\times 10^{24}\ kg\times 1.2\ kg}{(25370000\ m)^2}

F = 0.74 N

So, the force of gravity on the object is 0.74 N. Hence, this is the required solution.

5 0
4 years ago
What is total mechanical energy?
ollegr [7]

Answer:

is the energy possessed by an object due to either its motion or its stored energy of position. The total amount of mechanical energy is merely the sum of these two forms of energy. And finally, an object with mechanical energy is able to do work on another object.

Explanation:

5 0
3 years ago
A ladder 5.0 m long leans against a wall inside a spaceship. From the point of view of a person on the ship, the base of the lad
andriy [413]

Answer:

the angle the ladder makes with the floor as seen by an observer on Earth is 71.9°

Explanation:

Given the data in the question and as illustrated in the diagram below.

speed of the ship v = 0.90c

base of the ladder from the wall x₀ = 3.0 m

top of the later above the floor y = 4.0 m

we determine angle θ.

from the diagram,

tanθ = y/x₀

tanθ = y / x₀√( 1 - v²/c² )

we substitute

tanθ = 4.0 / 3.0√( 1 - ((0.9c)²/c²) )

tanθ = 4.0 / 3.0√( 1 - ((0.9²)c²/c²) )

tanθ = 4.0 / 3.0√( 1 - (0.9²) )

tanθ = 4.0 / 3.0√( 1 - 0.81 )

tanθ = 4.0 / 3.0√0.19

tanθ = 4.0 / 1.30766968

tanθ = 3.058876

θ = tan⁻¹( 3.058876 )

θ = 71.8965 ≈ 71.9°

Therefore, the angle the ladder makes with the floor as seen by an observer on Earth is 71.9°

3 0
3 years ago
edward travels 150 kilometers due west and then 200 kilometers in a direction 60 degrees north of west.what is his displacement
Naily [24]

The displacement of Edward in the westerly direction is determined as 338.32 km.

<h3>What is displacement of Edward?</h3>

The displacement of Edward can be determined from different methods of vector addition. The method applied here is triangular method.

The angle between the 200 km north west and 150 km west = 60 + 90 = 150⁰

The displacement is the side of the triangle facing 150⁰ = R

R² = a² + b² - 2abcosR

R² = 150² + 200²  - (2x 150 x 200)xcos(150)

R² = 62,500 - (-51,961.52)

R² = 114,461.52

R = 338.32 km

Learn more about displacement here: brainly.com/question/321442

#SPJ1

3 0
2 years ago
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