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natali 33 [55]
3 years ago
14

Next to each formula write the number of atoms of each element found in one unit of the compound - sodium sulfide

Chemistry
1 answer:
Fiesta28 [93]3 years ago
4 0
20 atoms i believe is correct 
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Aluminum fluoride contains only aluminum and fluorine. what is the formula for this compound?
attashe74 [19]
AlF3 would be the answer
3 0
3 years ago
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State the oxidation number assigned to each bold element in the formula: NH4+1 a 3 b -3 c -1 d 6
Leya [2.2K]
The fomula is NH4 (1+)


There are only two elements N and H.


As per oxidation state rules, the most electronegative element will have a negative oxidation state and the other element will have a positive oxidation state.


N is more electronative than H, so H will have a positive oxidation state and nitrogen will have a negative oxidation state.


You can also use the rule that states the hydrogen mostly has 1+ oxidation state,except when it is bonded to metals.


In conclusion the oxidation state of H in NH4 (1+) is 1+.


Now you must know that the sum of the oxidations states equals the charge of the ion, which in this case is 1+.


That implies that 4* (1+)  + x =   1+


=> x = (1+) - 4(+) = 3-


Answer:  the oxidation state of N is 3-, that is the option b.
8 0
3 years ago
1. Lab Investigator: Chemical Reactions cannot be used for
Elina [12.6K]

1: viewing any chemical reaction in a laboratory

2: dangerous to look at when it burns & used in photography, fireworks, and flares

3: the product

3 0
3 years ago
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What color is a mirror?
svp [43]

Depending what’s in front of a mirror

8 0
3 years ago
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Heating 235 g of water from 22.6°C to 94.4°C in a microwave oven requires 7.06 × 104 J of energy. If the microwave frequency is
Darya [45]

Answer: 3.69 × 10^27

Explanation:

Amount of energy required = 7.06 × 10^4 J

Frequency of microwave (f) = 2.88 × 10^10 s−1

Planck's constant (h) = 6.63 × 10^-34 Jᐧs/quantum

Recall ;

Energy of photon = hf

Therefore, energy of photon :

(6.63 × 10^-34)j.s× (2.88 × 10^10)s^-1

= 19.0944 × 10^(-34 + 10) = 19.0944×10^-24 J

Hence, number of quanta required :

(7.06 × 10^4)J / (19.0944 × 10^-24)J

= 0.369 × 10^(4 + 24) = 0.369×10^28

= 3.69 × 10^27

6 0
3 years ago
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