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daser333 [38]
3 years ago
12

6. Which of the following statements correctly describes what happens to the diaphragm during an

Chemistry
2 answers:
Ivenika [448]3 years ago
5 0

Answer:

O B. The diaphragm contracts and flattens.

Explanation:

The diaphragm is a skeletal striated muscle that separates the abdominal cavity from the thoracic cavity, has a dome shape and plays a key role in breathing.  Locate near the lumbar vertebrae, the lower ribs and the sternum and can be divided according to its location into three parts: sternal, costal and lumbar.

During inhalation, the diaphragm contracts and flattens, reducing the pressure inside the chest and compressing the viscera of the abdomen, which facilitates the entry of air into the lungs.

At the expiration, the inverse process occurs: it relaxes and rises, increasing the pressure inside the chest and expelling air from the lungs.

Crank3 years ago
3 0
Answer is B.

As the diaphragm contracts and flattens, it increases the volume of the thorax where the lungs are located. This results in a decrease in pressure (Boyle’s Law, if you know it) that creates a pressure gradient from outside to inside. This is what causes air to move into the lungs.
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Which of the following conditions will ensure that a chemical reaction will definitely proceed in the forward direction, toward
Grace [21]

Answer:

When ΔS > ΔH/ T, then the reaction will proceed forward

Explanation:

  • The entity that determines the whether a reaction will occur on its own in the forward direction (Spontaneity or Feasibility) is Gibb's free energy.
  • Gibb's free energy is the energy available to do work. It is denoted as 'G'. It cannot be easily measured. The change (ΔG) can only be measured.  ΔG = ΔH - TΔS

when ΔG is positive, The reaction is not spontaneous (reaction will not occur on its own)

When ΔG is negative, The reaction is spontaneous (reaction will occur on its own)

When ΔG is zero, the reaction is in equilibrium

Option A and E are not correct. ΔH (Enthalpy) cannot determine spontaneity

Option C and D cannot alone determine spontaneity of reaction

For reaction to be spontaneous, TΔS > ΔH

Therefore, ΔS > ΔH/T

4 0
3 years ago
At 25 ∘C the reaction CaCrO4(s)←→Ca2+(aq)+CrO2−4(aq) has an equilibrium constant Kc=7.1×10−4. What is the equilibrium concentrat
Nitella [24]

Answer:

2.67 × 10⁻²

Explanation:

Equation for the reaction is expressed as:

CaCrO₄(s)    ⇄      Ca₂⁺(aq)         +        CrO₂⁻⁴(aq)

Given that:

Kc=7.1×10⁻⁴

Kc= [Ca^{2+}][CrO^{2-}_4]

Kc= [x][x]

Kc= [x²]

7.1×10⁻⁴ =  [x²]

x = \sqrt{7.1*10^{-4}}

x = 0.0267

x = 2.67*10^{-2}

6 0
3 years ago
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Answer:

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Explanation:

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3 years ago
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gayaneshka [121]
I can't see the picture, but in general, I believe it is in dropping from the first energy level above the ground state, to the ground state.
6 0
3 years ago
Above is a solubility curve for KNO3.
Andrei [34K]

Answer:

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Explanation:

8 0
2 years ago
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