Answer:
Explanation:
We shall apply Stefan's formula
E = AσT⁴
When T = 300
I₁ = Aσ x 300⁴
When T = 400K
I₂ = Aσ x 400⁴
I₂ / I₁ = 400⁴ / 300⁴
= 256 / 81
= 3.16
I₂ = 3.16 I₁ .
Answer: The velocity with which the sand throw is 24.2 m/s.
Explanation:
Explanation:
acceleration due to gravity, a = 3.9 m/s2
height, h = 75 m
final velocity, v = 0
Let the initial velocity at the time of throw is u.
Use third equation of motion
The velocity with which the sand throw is 24.2 m/s.
Answer:
The atmospheric pressure is
.
Explanation:
Given that,
Atmospheric pressure
drop height h'= 27.1 mm
Density of mercury ![\rho= 13.59 g/cm^3](https://tex.z-dn.net/?f=%5Crho%3D%2013.59%20g%2Fcm%5E3)
We need to calculate the height
Using formula of pressure
![p = \rho g h](https://tex.z-dn.net/?f=p%20%3D%20%5Crho%20g%20h)
Put the value into the formula
![1.013\times10^{5}=13.59\times10^{3}\times9.8\times h](https://tex.z-dn.net/?f=1.013%5Ctimes10%5E%7B5%7D%3D13.59%5Ctimes10%5E%7B3%7D%5Ctimes9.8%5Ctimes%20h)
![h =\dfrac{1.013\times10^{5}}{13.59\times10^{3}\times9.8}](https://tex.z-dn.net/?f=h%20%3D%5Cdfrac%7B1.013%5Ctimes10%5E%7B5%7D%7D%7B13.59%5Ctimes10%5E%7B3%7D%5Ctimes9.8%7D)
![h=0.76\ m](https://tex.z-dn.net/?f=h%3D0.76%5C%20m)
We need to calculate the new height
![h''=h - h'](https://tex.z-dn.net/?f=h%27%27%3Dh%20-%20h%27)
![h''=0.76-27.1\times10^{-3}](https://tex.z-dn.net/?f=h%27%27%3D0.76-27.1%5Ctimes10%5E%7B-3%7D)
![h''=0.76-0.027](https://tex.z-dn.net/?f=h%27%27%3D0.76-0.027)
![h''=0.733\ m](https://tex.z-dn.net/?f=h%27%27%3D0.733%5C%20m)
We need to calculate the atmospheric pressure
Using formula of atmospheric pressure
![P=\rho g h](https://tex.z-dn.net/?f=P%3D%5Crho%20g%20h)
Put the value into the formula
![P= 13.59\times10^{3}\times9.8\times0.733](https://tex.z-dn.net/?f=P%3D%2013.59%5Ctimes10%5E%7B3%7D%5Ctimes9.8%5Ctimes0.733)
![P=0.97622\times10^{5}\ Pa](https://tex.z-dn.net/?f=P%3D0.97622%5Ctimes10%5E%7B5%7D%5C%20Pa)
Hence, The atmospheric pressure is
.
If my math is right its A) 7
because 189 divided by 27 is 7