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EastWind [94]
3 years ago
15

. The international space station has a mass of 4.2 x 105 kg and it orbits the Earth at an average altitude of 400 km above the

Earth's surface. The radius of the Earth is 6400 km, and the mass of the Earth is 6.0 x 1024 kg. Assume the only force acting on the space station is the Universal Gravitational Force, Fo, and assume that the orbit is perfectly circular. How long would it take for the space station to make one complete orbit around the Earth given these assumptions? A. 93 minutes B. 3.5 x 10 minutes C. 85 minutes D. 21 minutes E. 1.3 minutes
Physics
1 answer:
Tresset [83]3 years ago
5 0

Answer:

A. 93 min

Explanation:

M = mass of earth = 6.0 x 10²⁴ kg

R = Radius of earth = 6400 km = 6.4 x 10⁶ m

h = Altitude above earth = 400 km = 0.4 x 10⁶ m

Radius of orbit of the space station around earth is given as

r = R + h

r = 6400 + 400

r = 6800 km

r = 6.8 \times 10^{6} m

T = Time period of orbit of space station

Here we can use Kepler's third law which is given as

T^{2} = \frac{4\pi ^{2} r^{3}}{GM}

Inserting the above values

T^{2} = \frac{4(3.14)^{2} (6.8\times10^{6})^{3}}{(6.67\times10^{-11})(6.0\times10^{24})}

T^{2} = 3.1\times 10^{7}

T = 5566.53 sec

T = 5566.53 \left ( \frac{1min}{60sec} \right )= 93 min

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Answer:

a. by collisions and mergers of planetesimals.

Explanation:

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The main ingredient of these planets are solar nebula and interstellar dust condensation of which leads to formation of small rock particles. These particles come close to each other under in the influence of gravity and other forces. As the mass of the particles increase they form planetesimals, these planetesimals eventually merge to form planets.

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What are the consequences of sediment pollution?
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3 years ago
Describe how Heat is related to the internal energy
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Answer:

Thermal and internal energy is equal to the sum total kinetic energy possessed by the the molecules whereas the heat energy is the transfer of thermal energy from high temperature to low temperature.

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3 0
3 years ago
Explain why a Merry-Go-Round and a Ferris Wheel have a constant acceleration when they are moving.
luda_lava [24]

Explanation:What is centripetal acceleration?

Can an object accelerate if it's moving with constant speed? Yup! Many people find this counter-intuitive at first because they forget that changes in the direction of motion of an object—even if the object is maintaining a constant speed—still count as acceleration.

Acceleration is a change in velocity, either in its magnitude—i.e., speed—or in its direction, or both. In uniform circular motion, the direction of the velocity changes constantly, so there is always an associated acceleration, even though the speed might be constant. You experience this acceleration yourself when you turn a corner in your car—if you hold the wheel steady during a turn and move at constant speed, you are in uniform circular motion. What you notice is a sideways acceleration because you and the car are changing direction. The sharper the curve and the greater your speed, the more noticeable this acceleration will become. In this section we'll examine the direction and magnitude of that acceleration.

The figure below shows an object moving in a circular path at constant speed. The direction of the instantaneous velocity is shown at two points along the path. Acceleration is in the direction of the change in velocity, which points directly toward the center of rotation—the center of the circular path. This direction is shown with the vector diagram in the figure. We call the acceleration of an object moving in uniform circular motion—resulting from a net external force—the centripetal acceleration

a

c

a

c

​

a, start subscript, c, end subscript; centripetal means “toward the center” or “center seeking”.

5 0
3 years ago
A 1.31 kg object is attached to a horizontal spring of force constant 2.70 N/cm and is started oscillating by pulling it 6.20 cm
goldfiish [28.3K]

Answer:

The answer is below

Explanation:

a) The change in energy is the difference between the final energy and the initial energy.

ΔE (energy change) = Ef (final energy) - Ei (initial energy)

\Delta E=\frac{1}{2}kA_f^2 -\frac{1}{2}kA_i^2\\\\k=force\ constant=2.7\ N/cm=270\ N/m, A_f=final\ dispalacment= 3.7\ cm=0.037\ m,\\ A_i=initial \ displacement = 6.2\ cm=0.062\ m\\\\Hence:\\\\\Delta E=\frac{1}{2}(270)(0.037)^2 -\frac{1}{2}(270)(0.062)^2\\\\\Delta E=-0.334 \ J

The negative sign shows that energy is lost to the environment. Hence 0.334 J is lost to the environment.

b) According to the law of conservation of energy, energy cannot be created or destroyed but transformed from one form to another.

The oscillating object loses energy due to wind resistance, friction between the spring and the object. Given that the air is frictionless, hence the energy loss is due to friction which is converted to heat.

6 0
3 years ago
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