Ask question

Ask question

All categories

3 years ago

9

Use the data provided to calculate the gravitational potential energy of each cylinder mass. Round your answers to the nearest t

enth.
3 kg: kJ
6 kg: kJ
9 kg: kJ

2 answers:

pantera1 [17]3 years ago

7 0

Answer: 3kg: 14.7 6kg: 29.4 9kg: 44.1

Explanation: just did it on Edge

PIT_PIT [208]3 years ago

5 0

Answer:

Explanation:

3 kg 14.7

6kg 29.4

9kg 44.1

You might be interested in

A mover loads a crate onto a truck bed 1.6m from the street using a ramp that is 4.6m long. What is a mechanical advantage?

Ne4ueva [31]

Answer:

Mechanical advantage = 2.875

Explanation:

Given:

A diagram is shown below for the above scenario.

Length of ramp (Effort arm) = 4.6 m

Height of truck bed ( Resistance length) = 1.6 m

Mechanical advantage (MA) is the ratio of effort arm and resistance length.

So, mechanical advantage is given as,

$MA=\frac{\textrm{Effort arm}}{\textrm{Resistance length}}= \frac{4.6}{1.6}=2.875$

6 0

3 years ago

Which of the fundamental forces explains the structure of atoms and molecules?

spayn [35]

The electromagnetic force<span> holds atoms and molecules together.
like a magnet's pull on steel.</span>

7 0

3 years ago

Read 2 more answers

What percentage of the earth's surface is covered in water

Alla [95]

Answer:

71 % of the earth's surface is covered in water

8 0

3 years ago

Read 2 more answers

A car accelerate from a stop to 27 m/sec in 5 seconds. What was the car's acceleration?

Furkat [3]

The acceleration should 5.4 m/s^2

4 0

3 years ago

A 594 Ω resistor, an uncharged 1.3 μF capacitor, and a 6.53 V emf are connected in series. What is the current in milliamps afte

ivanzaharov [21]

Answer:

6.88 mA

Explanation:

Given:

Resistance, R = 594 Ω

Capacitance = 1.3 μF

emf, V = 6.53 V

Time, t = 1 time constant

Now,

The initial current, I₀ = $\frac{\textup{V}}{\textup{R}}$

or

I₀ = $\frac{\textup{6.53}}{\textup{594}}$

or

I₀ = 0.0109 A

also,

I = $I_0[1-e^{-\frac{t}{\tau}}]$

here,

τ = time constant

e = 2.717

on substituting the respective values, we get

I = $0.0109[1-e^{-\frac{\tau}{\tau}}]$

or

I = $0.0109[1-2.717^{-1}]$

or

I = 0.00688 A

or

I = 6.88 mA

5 0

3 years ago