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3 years ago

9

Use the data provided to calculate the gravitational potential energy of each cylinder mass. Round your answers to the nearest t

enth.
3 kg: kJ
6 kg: kJ
9 kg: kJ

2 answers:

pantera1 [17]3 years ago

7 0

Answer: 3kg: 14.7 6kg: 29.4 9kg: 44.1

Explanation: just did it on Edge

PIT_PIT [208]3 years ago

5 0

Answer:

Explanation:

3 kg 14.7

6kg 29.4

9kg 44.1

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What is the mass of an object that is 6kg on a planet with an acceleration due to gravity

goldfiish [28.3K]

Answer:

Mass of the body will be = 6 kg

Explanation:

Given:

Mass of an object = 6 kg

Acceleration due to gravity of the planet = 10 $m/s^2$

To find the mass of the body on that planet.

Solution:

Mass of the body is defined as the total amount of matter contained in the body.

Thus, mass of a body will always remain constant irrespective of the acceleration due to gravity. This is because it is an independent quantity and does not vary with acceleration due to gravity.

<em>It is the weight of the body that changes with the change in the acceleration due to gravity as it is given by:</em>

$W=mg$

where $m$ represents mass of the body and $g$ represents the accelration due to gravity.

Hence, the mass of the given body will remain = 6 kg.

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3 years ago

Can anybody please help? 15 points pls

Mariana [72]

Acceleration= v/ r
So you have to divide 700 by 0.800 which is equal to 875 m/s 2

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3 years ago

If the amplitude of a sound wave is tripled, by what factor will the intensity increase?

Shtirlitz [24]

Answer:

By a factor 9

Explanation:

The intensity of a sound wave is proportional to the square of the amplitude of the wave:

$I \propto A^2$

where

I is the intensity

A is the amplitude of the wave

In this problem, the amplitude of the sound wave is increased by a factor 3:

A' = 3A

So the intensity would change by

$I' \propto A'^2 = (3A)^2 = 9 A^2 = 9I$

So, the intensity would increase by a factor 9.

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3 years ago

As the human population continues to grow, sustainability measures must be put into place. Smart growth is a theoretical practic

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Answer:

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3 years ago

The engine starter and a headlight of a car are connected in parallel to the 12.0-V car battery. In this situation, the headligh

stepladder [879]

Answer:

The total power they will consume in series is approximately 2.257 W

Explanation:

The connection arrangement of the headlight and the engine starter = Parallel to the battery

The voltage of the battery, V = 12.0 V

The power at which the headlight operates in parallel, $P_{headlight}$ = 38 W

The power at which the kick starter operates in parallel, $P_{kick \ starter}$ = 2.40 kW

We have;

P = V²/R

Where;

R = The resistance

V = The voltage = 12 V (The voltage is the same in parallel circuit)

For the headlight, we have;

R₁ = V²/ $P_{headlight}$ = 12²/38 = 72/19

R₁ = 72/19 Ω

For the kick starter, we have;

R₂ = V²/ $P_{kick \ starter}$ = 12²/2.4 = 60

R₂ = 60 Ω

When the headlight and kick starter are rewired to be in series, we have;

Total resistance, R = R₁ + R₂

Therefore;

R = ((72/19) + 60) Ω = (1212/19) Ω

The current flowing, I = V/R

∴ I = 12 V/(1212/19) Ω = (19/101) A

We note that power, P = I²R

In the series connection, we have;

$P_{headlight}$ = I² × R₁

∴ $P_{headlight}$ = ((19/101) A)² × 72/19 Ω = 1368/10201 W ≈ 0.134 W

The power at which the headlight operates in series, $P_{headlight, S}$ ≈ 0.134 W

$P_{kick \ starter}$ = ((19/101) A)² × 60 Ω = 21660/10201 W ≈ 2.123 W

The power at which the kick starter operates in series, $P_{kick \ starter, S}$ ≈ 2.123 W

The total power they will consume, $P_{Total}$ = $P_{headlight, S}$ + $P_{kick \ starter, S}$

Therefore;

$P_{Total}$ ≈ 0.134 W + 2.123 W = 2.257 W

4 0

3 years ago