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Nastasia [14]
3 years ago
8

Sodium chloride, NaCl find molar mass

Chemistry
2 answers:
marta [7]3 years ago
8 0
Hahaha silly me I forgot what NaCA was haha
castortr0y [4]3 years ago
4 0
<span>Now, since the compound NaCl is made of sodium and chlorine, the molar mass of NaCl can be calculated only after its atomic weight is known from the table. Individual atoms of sodium and chlorine have an atomic mass of 22.98976 g/mol and 35.453 g/mol respectively.


BRAINLIEST???</span>
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Identifying a trend in temperature change over time
stiv31 [10]

Answer:

More than three decade the temperature of earth is increasing equally by the rate of 0.8 Celsius (1.4 Fahrenheit). It is going to be very harmful for the human being as well animals.  The global warming is the main reason and hole in the ozone layer had been the cause of increasing the temperature of the earth. Humans are also involved in cause in temperature of earth by cutting forests and making land suitable for residence and not planting more trees instead of the cut trees.

7 0
3 years ago
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What are some limitations of this experiment? How could it be improved?
solong [7]

Answer: Limitation: They may be more expensive and time consuming than lab experiments. Limitation: There is no control over extraneous variables that might bias the results. This makes it difficult for another researcher to replicate the study in exactly the same way.

Explanation:

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3 0
2 years ago
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A 32 L samples of xenon gas at 10°C is expanded to 35 L. Calculate the final temperature.
morpeh [17]

Answer:

              Final Temperature = 36.54 ⁰C

Explanation:

Lets suppose the gas is acting ideally, then according to Charle's Law, "<em>The volume of a fixed mass of gas at constant pressure is directly proportional to the absolute temperature</em>". Mathematically for initial and final states the relation is as follow,

                                                V₁ / T₁  =  V₂ / T₂

Data Given;

                  V₁  =  32 L

                  T₁  =  10 °C = 283.15 K             ∴ K = °C + 273.15

                  V₂  =  35 L

                  T₂  =  ??

Solving equation for T₂,

                         T₂  =  V₂ × T₁  / V₁

Putting values,

                         T₂  =  (35 L × 283.15 K) ÷ 32 L

                         T₂  =  309.69 K     ∴ ( 36.54 °C )

Result:

           As the volume is increased from 32 L to 35 L, therefore, the temperature must have increased from 10 °C to 36.54 °C.

3 0
3 years ago
An aqueous solution that has a hydrogen ion concentration of 1.0 x 10^-8 mole per liter has a pH of
spin [16.1K]

Answer: 8, which is basic

Explanation: The hydrogen ion concentration is 1.0 x 10^-8 mole per liter. Using [H+] = 1.0 x 10 -(pH) the pH is 8. A pH above 7 is basic.

7 0
2 years ago
Calculate the percent ionization of propionic acid (C2H5COOH) in solutions of each of the following concentrations (Ka is given
tekilochka [14]

Answer:

a) = 0.704%

b) = 1.30%

c) = 2.60%

Explanation:

Given that:

K_a= 1.34*10^{-5

For Part A; where Concentration of A = 0.270 M

Percentage Ionization(∝)  \alpha = \sqrt{\frac{K_a}{C} }

\alpha = \sqrt{\frac{1.34*10^{-5}}{0.270} }

\alpha = \sqrt{4.9629*10^{-5}}

\alpha = 7.044*10^{-3

percentage% (∝) = 7.044*10^{-3}*100

= 0.704%

For Part B; where Concentration of B = 7.84*10^{-2 M

\alpha = \sqrt{\frac{1.34*10^{-5}}{7.84*10^{-2}} }

\alpha = \sqrt{1.709*10^{-4} }

\alpha = 0.0130\\

percentage% (∝) = 0.0130 × 100%

= 1.30%

For Part C; where Concentration of C= 1.92*10^{-2} M

\alpha = \sqrt{\frac{1.34*10^{-5}}{1.97*10^{-2}} }

\alpha = \sqrt{6.802*10^{-4}}

\alpha =0.02608

percentage% (∝) = 0.02608  × 100%

= 2.60%

7 0
3 years ago
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