%yield = 88.5%
<h3>Further explanation</h3>
Given
Reaction
Cu(s) + 2 AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s)
Required
The percent yield
Solution
mol AgNO₃(MW=169,87 g/mol) :
= mass : MW
= 127 : 169.87
= 0.748
mol Ag from equation :
= 2/2 x mol AgNO₃
= 2/2 x 0.748
= 0.748
Mass Ag (theoretical) :
= mol x Ar Ag
= 0.748 x 108
= 80.784
% yield = (actual/theoretical) x 100%
%yield = 71.5/80.784 x 100%
<em>%yield = 88.5%</em>
The coefficient in a chemical formula represents the amount of each chemical present. The amount of a substance is measured in moles.
I can try.
Whats the question
This would problem will be answered using the concept of momentum. Momentum is the mass times the velocity, where mass is inversely proportional to the velocity. This would mean that an object with greater mass will travel at a much lesser velocity, or vice versa.
Hence, the cart with the smaller mass will accelerate faster.
The mass of the liquid is 4.8 kg.
6.4 L = 6400 mL
Mass = 6400 mL × (0.70 g/1 mL) = 4500 g = 4.8 kg
