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Anna [14]
2 years ago
13

Calculate the molar mass of aluminum oxide (Al2O3). Express your answer to four significant figures.

Chemistry
1 answer:
a_sh-v [17]2 years ago
6 0

Answer:

102.0 g/mol.

Explanation:

Aluminum oxide  or Al2O3 is a chemical compound composed of 3 Oxygen and 2 aluminum atoms. Naturally, it is present in the form of mineral corundum in crystalline polymorphic forms. It holds significant importance in the preparation of Aluminium metal that is used as a refractory material.

To calculate the molar mass of Aluminum oxide, we will add the molar mass of 2 Al and 3 O atoms.

                         Since molar mass of Al is: 26.98 g

                               Molar mass of O is: 16.00 g

                                   Molar mass of Al2O3

                                  =   (26.98)2 +  (16.00) 3

                                     =    53.96 +   48

                                       = 101.96 g/mol

Since it is mentioned in question to round off the answer upto 4 significant figures, it will make the answer: 102.0 g/mol.

Hope it help!

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A 2.5 L flask is filled with 0.25 atm SO3, 0.20 atm SO2, and 0.40 atm O2, and allowed to reach equilibrium. Assume at the temper
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Explanation:

Reaction equation for the given chemical reaction is as follows.

      2SO_{3} \rightleftharpoons 2SO_{2} + O_{2}

Equation for reaction quotient is as follows.

         Q = \frac{P^{2}_{SO_{2}} \times P_{O_{2}}}{P^{2}_{SO_{3}}}

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As, Q > K (= 0.12)

The effect on the partial pressure of SO_{3} as equilibrium is achieved by using Q, is as follows.

  • This means that there are too much products.
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3 years ago
PLS HELP ME WITH THESE I WILL MARK U AS BRAINLIEST!!
netineya [11]

Answer:

uy pasagot kung nasagutan mo na pls wala pa akong sagot jan

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Answer:

18.9 moles of MgCl2 = 17.834 kg of MgCl2

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Considering the original question was in the context of chemistry, I wanted to make it seem formal and more educational too. Hopefully that worked!  

EDIT: Came up with some text around what happens inside cells that would have made it better if someone just had an issue converting units, but I doubt my answer will be accepted >.<

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2 years ago
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