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Anna [14]
3 years ago
13

Calculate the molar mass of aluminum oxide (Al2O3). Express your answer to four significant figures.

Chemistry
1 answer:
a_sh-v [17]3 years ago
6 0

Answer:

102.0 g/mol.

Explanation:

Aluminum oxide  or Al2O3 is a chemical compound composed of 3 Oxygen and 2 aluminum atoms. Naturally, it is present in the form of mineral corundum in crystalline polymorphic forms. It holds significant importance in the preparation of Aluminium metal that is used as a refractory material.

To calculate the molar mass of Aluminum oxide, we will add the molar mass of 2 Al and 3 O atoms.

                         Since molar mass of Al is: 26.98 g

                               Molar mass of O is: 16.00 g

                                   Molar mass of Al2O3

                                  =   (26.98)2 +  (16.00) 3

                                     =    53.96 +   48

                                       = 101.96 g/mol

Since it is mentioned in question to round off the answer upto 4 significant figures, it will make the answer: 102.0 g/mol.

Hope it help!

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Sulfur dioxide, SO2(g), can react with oxygen to produce sulfur trioxide, SO3(g), by the following reaction
WITCHER [35]

Answer:

The heat produced is -15,1kJ

Explanation:

For the reaction:

2SO₂+O₂ → 2SO₃

The enthalpy of reaction is:

ΔHr = 2ΔHf SO₃ - 2ΔHf SO₂

As ΔHf SO₃ = -395,7kJ and ΔHf SO₂ = -296,8kJ

<em>ΔHr = -197,8kJ</em>

Using n=PV/RT, the moles of reaction are:

n = \frac{1,00atm*3,75L}{0,082atmL/molK*298,15K} = <em>0,153 moles of reaction</em>

As 2 moles of reaction produce -197,8kJ of heat, 0,153moles produce:

0,153mol×\frac{-197,8kJ}{2mol} = <em>-15,1kJ</em>

<em></em>

I hope it helps!

8 0
3 years ago
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I think the answer would be b
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The number of glyceraldehyde-3-phosphate molecules that would be produced from 24 turns of the calvin cycle would be
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The Calvin cycle, also called the light-independent or carbon fixation reactions, is the second stage of photosynthesis where water, and carbon dioxide (CO2) from air, are converted into organic compounds (i.e. sugars) using the energy from short-lived electronically excited carriers (ATP and NADPH) for the reactions. These organic compounds can then be used by the producing organism (i.e. plants) and the animals that feed on it. 

One product of the Calvin cycle is the glyceraldehyde-3-phosphate (G3P), which is later on used in the production of glucose and in the regeneration of <span>Ribulose 1,5-bisphosphate (RuBP), which is an organic compound</span> essential to the reactions in the cycle. 

One turn of Calvin Cycle produces 2 G3P molecules, each comprising of 3 carbons. This gives a total of 6 carbons. Five (5) of these carbons will be used to regenerate RuBP and only 1 will be available to form a surplus G3P later on. This surplus G3P will be used for the production of glucose (a 6-carbon sugar). 

Thus, 3 turns of the carbon cycle will produce 1 surplus G3P. There are 8 sets of 3-turns in 24 cycles, therefore, 

                       1 net G3P molecule * 8 sets of 3-turns  = 8 G3P molecules

Therefore, there are 8 net or surplus G3P molecules produced for 24 cycles of the Calvin Cycle. The total G3P molecules produced, including the ones that participated in the regeneration of RuBP would be 48 G3Ps. 

For every 3 turns, 6 G3P molecules are produced, 5 of which will be used in the regeneration of RuBP and 1 will be the net or surplus, to be used for the production of glucose. The 48 G3Ps then come from the calculation, 

                       6 total G3P molecules * 8 sets of 3-turns  = 48 G3P molecules


The figure below shows the products of the cycle after 3 turns (Source: https://ka-perseus-images.s3.amazonaws.com/2f4bdc8f8275834d3f5ef434d93bf16b991b2357.png). 

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