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sladkih [1.3K]
2 years ago
5

Question 10 How many oxygen atoms are in the chemical formula Al(PO4)3? O 1 O 12 O 3​

Chemistry
2 answers:
Basile [38]2 years ago
5 0
13 atoms are in the chemical formula AI(PO4)3
hope that helps :-)
sammy [17]2 years ago
3 0
12 oxygen atoms in this question
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A bomb calorimetric experiment was run to determine the enthalpy of combustion of ethanol. The reaction is The bomb had a heat c
gulaghasi [49]

Answer:

The enthalpy of combustion of ethanol in kJ/mol is -1419.58  kJ/mol.

Explanation:

The heat absorbed by the bomb and water is equal to the product of the heat  capacity and the temperature change. Working with this equation, and assuming no heat is lost to  the surroundings, we write :

qcal= Ccal × ΔT= 490 J/K × 276.7 K= <u>135,583 J</u> = 135.58 kJ

Note we expressed the temperature change in K, because the heat capacity is written in K.

<u> Now that we have the heat of combustion, we need to calculate the molar heat.  </u>

Because qsystem = qrxn + qcal and qrxn = -qcal, the heat change of the reaction is -135.58 kJ.

This is the heat released by the combustion of 4.40 g of ethanol ; therefore, we can write  the <u>conversion factor as 135.58 kJ/ 4.40 g</u>.

The molar mass of ethanol is 46.07 g, so the heat of combustion of 1 mole of ethanol is :

molar heat of combustion= -135.58 kJ/4.40 g x 46.07 g/ 1 mol= -1419.58 kJ/mol

Therefore, the enthalpy of combustion of ethanol in kJ/mol is -1419.58  kJ/mol.

3 0
3 years ago
1 pentagram equals how many grams
Fofino [41]

Answer:

5 grams.

Explanation:

Anything that weighs 5 grams, technically, is a pentagram.

7 0
3 years ago
What is a example of a population​
lbvjy [14]

Answer:

how much people there are example a small town have 500 people living in that town

4 0
3 years ago
How to calculate work done with change in volume and pressure.
natali 33 [55]

W = \displaystyle \int dW  = \displaystyle \int^{V_2}_{V_1}  p ~dV = p(V_2 - V_1) = p \Delta V

3 0
2 years ago
Write the net ionic equation for the precipitation reaction that occurs when aqueous solutions of ammonium phosphate and nickel(
densk [106]

Answer:

2PO_4^{3-}(aq)+3Ni^{2+}(aq)\rightarrow Ni_3(PO_4)_2(s)

Explanation:

Hello,

In this case, the molecular chemical reaction is:

(NH_4)_3PO_4(aq)+NiBr_2(aq)\rightarrow NH_4Br(aq)+Ni_3(PO_4)_2(s)

Thus, by considering the ionic species we have:

NH_4^+(aq)+2PO_4^{3-}(aq)+3Ni^{2+}(aq)+Br^-(aq)\rightarrow NH_4^+(aq)+Br^-(aq)+Ni_3(PO_4)_2(s)

Wherein the ammonium and bromide ions are spectator ions since nickel (II) phosphate is largely insoluble in water, therefore, the net ionic equation is:

2PO_4^{3-}(aq)+3Ni^{2+}(aq)\rightarrow Ni_3(PO_4)_2(s)

Best regards.

7 0
3 years ago
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