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3 years ago

What is the resistance force when you walk up an inclined plane?

Physics

1 answer:

erastovalidia [21]3 years ago

8 0

Answer:

the resistance force is mg cos(-)

Explanation:

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What is the definition of Cubit

disa [49]

Answer:

See below.

Explanation:

Cubit is a unit of length based on the length of the forearm from the elbow to the tip of the middle finger and usually equal to about 18 inches (46 centimeters).

It is an ancient unit of length used in ancient Egypt and is also known as "ancient Egyptian royal cubit."

Other similar units of measurements are displayed in the image below. Thanks!

7 0

2 years ago

How many ways can motion change

meriva

Answer:

There are four main ways of doing that :-

Velocity
Acceleration
Momentum
Kinetic energy

Hope it helps!

7 0

3 years ago

Read 2 more answers

A liquid is used to make a mercury-type barometer. The barometer is intended for space-faring astronauts. At the surface of the

Anarel [89]

Answer:

Density of liquid = 4730 kg/m³

Atmospheric pressure on planet X = 8401.7 N/m²

Explanation:

Pressure, P = ρgh where ρ = density of liquid, g =9.8 m/s² and h = height of column at earth's surface = 2185 mm. Since P = atmospheric pressure, for mercury, P = ρ₁gh₁ where ρ₁ = 13.6 g/cm³ and h₁ = 760 mm

So, ρgh = ρ₁gh₁

ρ = ρ₁h₁/h = 13.6 g/cm³ × 760/2185 = 4.73 g/cm³ = 4730 kg/m³

The atmospheric pressure on planet X

P = ρg₁h₃ g₁ = g/4 and h₃ = 725 mm = 0.725 m

on planet X

P = ρg₁h₃ = (4730 kg/m³ × 9.8 m/s² × 0.725 m)/4 = 8401.7 N/m²

6 0

3 years ago

In designing a backyard water fountain, a gardener wants to stream of water to exit from the bottom of one tub and land in a sec

mote1985 [20]

To solve this problem it is necessary to apply the concepts related to the kinematic equations of movement description.

From the definition we know that the speed of a body can be described as a function of gravity and height

$V = \sqrt{2gh}$

$V = \sqrt{2*9.8*0.15}$

$V = 1.714m/s$

Then applying the kinematic equation of displacement, the height can be written as

$H = \frac{1}{2}gt^2$

Re-arrange to find t,

$t = \sqrt{2\frac{h}{g}}$

$t = \sqrt{2\frac{0.5}{9.8}}$

$t = 0.3194s$

Thus the calculation of the displacement would be subject to

$x = vt$

$x =1.714*0.3194$

$x = 0.547m$

Therefore the required distance must be 0.547m

4 0

3 years ago

The 49-g arrow is launched so that it hits and embeds in a 1.45 kg block. The block hangs from strings. After the arrow joins th

Dimas [21]

Answer:

the initial speed of the arrow before joining the block is 89.85 m/s

Explanation:

Given;

mass of the arrow, m₁ = 49 g = 0.049 kg

mass of block, m₂ = 1.45 kg

height reached by the arrow and the block, h = 0.44 m

The gravitational potential energy of the block and arrow system;

P.E = mgh

P.E = (1.45 + 0.049) x 9.8 x 0.44

P.E = 6.464 J

The final velocity of the system after collision is calculated as;

K.E = ¹/₂mv²

6.464 = ¹/₂(1.45 + 0.049)v²

6.464 = 0.7495v²

v² = 6.464 / 0.7495

v² = 8.6244

v = √8.6244

v = 2.937 m/s

Apply principle of conservation of linear momentum to determine the initial speed of the arrow;

$P_{initial} = P_{final}\\\\mv_{arrow} + mv_{block} = (m_1 + m_2)V\\\\0.049(v) + 1.45(0) = (0.049 + 1.45)2.937\\\\0.049v = 4.4026\\\\v = \frac{4.4026}{0.049} \\\\v = 89.85 \ m/s$

Therefore, the initial speed of the arrow before joining the block is 89.85 m/s

4 0

2 years ago