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murzikaleks [220]
2 years ago
8

A rollercoaster accelerates from 10 m/s to 100 m/s2 for 25 seconds. What is the acceleration?

Physics
1 answer:
UkoKoshka [18]2 years ago
5 0

Answer:

A roller coasters accelerates from an initial velocity of of 6.0 m/s to a final velocity of 70 m/s over 4 seconds. What's the acceleration? Q. Acceleration only takes place when things speed up. Q. A drag racer accelerated from 0 m/s to 200 m/s in 5 s.

Explanation:

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Evgesh-ka [11]

Answer:

Element or a compound.

Explanation:

6 0
3 years ago
Study the velocity vs. time graph shown.
laiz [17]

For velocity vs Time graphs, the displacement of the object from 2 seconds to 6 seconds is 30 m.

<h3>What is displacement?</h3>

The displacement is the shortest distance travelled by the particle. It is the vector quantity which re[presents both the magnitude and direction.

In velocity time graphs, the displacement is the area under the curve of the graph on the x axis.

'

A line starts at (0, 2) and ends at (6, 8) in v-t graph

Displacement is equal to the area of a triangle and a rectangle formed under the line.

Area = 1/2 base x height + length x breadth

Area = 1/2 x 6x 6 + 6x2

Area = 18 +12

Area = 30 m

Thus, the displacement is 30 m.

Learn more about displacement.

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6 0
2 years ago
A(n) ______ particle consists of two protons and neutrons.
solniwko [45]
The correct answer is alpha
3 0
3 years ago
Read 2 more answers
I've got an energy and work problem. The premise of the problem is:
Alenkasestr [34]
Refer to the diagram shown below.

μ =  the coefficient of dynamic friction between the crate and the ramp.

1. The applied force of F acts over a distance, d.
    The work done is F*d.

2. The component of the weight of the crate acting down the ramp is
    mg sin(30) = 0.5mg. 
    The work done by this force is 0.5mgd.

3. The normal force is N = mgcos(30) = 0.866mg.
     This force is perpendicular to the ramp, therefore the work done is zero.

4. The frictional force is μN = μmgcos(30) = 0.866μmg.
    The work done by the frictional force is 0.866μmgd.

5. The total force acting on the crate up the ramp is
     F - mgsin(30) - μmgcos(30) = F - mg(0.5 - 0.866μ) 

6. The work done on the crate by the total force is
    d*(F - 0.5mg - 0.866μmg)

7 0
3 years ago
When the resistance in a circuit remains constant, how are the voltage and current related?
solmaris [256]
V=IR, therefore when resistance is constant the voltage and current are directly proportional
6 0
3 years ago
Read 2 more answers
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