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denis-greek [22]
1 year ago
8

If the average density of the Universe is small compared with the critical density, the expansion of the Universe described by H

ubble's law proceeds with speeds that are nearly constant over time. (a) Prove that in this case the age of the Universe is given by the inverse of the Hubble constant.
Physics
1 answer:
Ratling [72]1 year ago
7 0

(a) v=HR defines the Hubble constant. According to R=vt, the gap R between any two far-separated objects opens at a constant speed. The time interval t since the Big Bang is then calculated.

v=HvΔt→Δt=\frac{1}{H}

<h3>What exactly is the Hubble constant?</h3>

  • Hubble constant, in cosmology, a proportionality constant in the relationship between the velocities of distant galaxies and their distances.
  • It expresses the rate of expansion of the universe. It is represented by the symbol H_{0}, with the subscript indicating that the value is measured at the present time, and is named after Edwin Hubble, an American astronomer who attempted to measure its value in 1929.
  • Hubble established the cosmological velocity-distance law using redshifts of distant galaxies measured by Vesto Slipher, also of the United States, and his own distance estimates for these galaxies:
  • H_{0} distance = velocity

To learn more about Hubble constant refer to

brainly.com/question/26117248

#SPJ4

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Hello people ~
o-na [289]

Answer:

<u>(B) wheat</u>

Explanation:

  • Wheat is an <u>anemophilous</u> plant (form of pollination by which wind distributes pollen)
  • They lack petals and sepals (outer whorls of the flower)
  • The female plants consist of an ovary (female reproductive part) from which two styles (connecting stigma and ovary) arise
  • The feathery stigma catches the pollen and sends it to the ovary for fertilization
6 0
2 years ago
Read 2 more answers
A student pushes on a 8-kg box with a force of 35 N forward. The force of sliding friction is 10 N backward. What is the acceler
Ne4ueva [31]

Answer:

(35 N - 10 N)/8kg = 3.125 m/s^2

Explanation:

The formula for Force is:

Force = Mass*Acceleration

(Force is equal to Mass times Acceleration)

Since we're told to find the acceleration of the box. We make acceleration the subject of the equation:

Acceleration = Force/Mass

(Acceleration equal to Force divided by Mass)

We know that the force are 35 N forward and 10 N backward, and the weight of the box is 8kg.

= (35 N - 10 N)/8kg

The reason that 35 N minus 10 N is because the 10 N is pushing the box backward.

= 25 N/8kg

= 3.125 m/s^2

Hope it helps :DD

3 0
3 years ago
A torque of 36.5 N · m is applied to an initially motionless wheel which rotates around a fixed axis. This torque is the result
vivado [14]

Answer:

21.6\ \text{kg m}^2

3.672\ \text{Nm}

54.66\ \text{revolutions}

Explanation:

\tau = Torque = 36.5 Nm

\omega_i = Initial angular velocity = 0

\omega_f = Final angular velocity = 10.3 rad/s

t = Time = 6.1 s

I = Moment of inertia

From the kinematic equations of linear motion we have

\omega_f=\omega_i+\alpha_1 t\\\Rightarrow \alpha_1=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha_1=\dfrac{10.3-0}{6.1}\\\Rightarrow \alpha_1=1.69\ \text{rad/s}^2

Torque is given by

\tau=I\alpha_1\\\Rightarrow I=\dfrac{\tau}{\alpha_1}\\\Rightarrow I=\dfrac{36.5}{1.69}\\\Rightarrow I=21.6\ \text{kg m}^2

The wheel's moment of inertia is 21.6\ \text{kg m}^2

t = 60.6 s

\omega_i = 10.3 rad/s

\omega_f = 0

\alpha_2=\dfrac{0-10.3}{60.6}\\\Rightarrow \alpha_1=-0.17\ \text{rad/s}^2

Frictional torque is given by

\tau_f=I\alpha_2\\\Rightarrow \tau_f=21.6\times -0.17\\\Rightarrow \tau=-3.672\ \text{Nm}

The magnitude of the torque caused by friction is 3.672\ \text{Nm}

Speeding up

\theta_1=0\times t+\dfrac{1}{2}\times 1.69\times 6.1^2\\\Rightarrow \theta_1=31.44\ \text{rad}

Slowing down

\theta_2=10.3\times 60.6+\dfrac{1}{2}\times (-0.17)\times 60.6^2\\\Rightarrow \theta_2=312.03\ \text{rad}

Total number of revolutions

\theta=\theta_1+\theta_2\\\Rightarrow \theta=31.44+312.03=343.47\ \text{rad}

\dfrac{343.47}{2\pi}=54.66\ \text{revolutions}

The total number of revolutions the wheel goes through is 54.66\ \text{revolutions}.

3 0
3 years ago
An object floats in a beaker as shown. when it was put into the beaker, it displaced an amount of water into the graduated cylin
Tanzania [10]

Answer:

answer is  C. 10 g

Explanation:

: When an object floats, it displaces an amount of water that has the same mass as itself. Therefore, the mass of the water in the graduated cylinder is equal to the mass of the object. We can see that there are 10 mL of water in the graduated cylinder. We also know that the density of water is 1 g/mL. Since each mL of water has a mass of 1 g, then 10 mL of water has a mass of 10 g. If the mass of the displaced water is 10 g, then the mass of the floating object is also 10 g.

6 0
2 years ago
Definition of artficial and natural radioactivity​
Genrish500 [490]
Search Results
Featured snippet from the web
The spontaneous emission of radiations from an unstable nuclei is known as natural radioactivity. on the other hand, The process of emission of radiations from naturally occurring isotopes when they are bombarded with sub-atomic particles or high levels of X-rays or gamma rays called artificial radioactivity.
8 0
2 years ago
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