Question

If the average density of the Universe is small compared with the critical density, the expansion of the Universe described by Hubble's law proceeds with speeds that are nearly constant over time. (a) Prove that in this case the age of the Universe is given by the inverse of the Hubble constant.

Answer 1

(a) v=HR defines the Hubble constant. According to R=vt, the gap R between any two far-separated objects opens at a constant speed. The time interval t since the Big Bang is then calculated.

v=HvΔt→Δt=$\frac{1}{H}$

What exactly is the Hubble constant?

• Hubble constant, in cosmology, a proportionality constant in the relationship between the velocities of distant galaxies and their distances.
• It expresses the rate of expansion of the universe. It is represented by the symbol $H_{0}$, with the subscript indicating that the value is measured at the present time, and is named after Edwin Hubble, an American astronomer who attempted to measure its value in 1929.
• Hubble established the cosmological velocity-distance law using redshifts of distant galaxies measured by Vesto Slipher, also of the United States, and his own distance estimates for these galaxies:

• $H_{0}$ distance = velocity

To learn more about Hubble constant refer to

brainly.com/question/26117248

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