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Irina18 [472]
3 years ago
5

Euglena are _______. A heterotrophs B autotrophs

Physics
1 answer:
zysi [14]3 years ago
6 0
The Euglena is unique in that it is both heterotrophic (must consume food) and autotrophic (can make its own food).
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A taxi starts from Monument Circle and travels 5 kilometers to the east for 5 minutes. Then it travels 10 kilometers to the sout
katovenus [111]

The correct sentence is:

The taxi is moving with reference to  A) Monument circle. For each leg of the trip, the taxi’s  A) Average speed stays the same, but its  B) Average velocity  changes.

In fact, speed it is only the ratio between the distance traveled and the time taken - so it does not take into account the direction of motion. The speed in the first leg is

v=\frac{5 km}{5 min}=1 km/min

while the speed in the second leg is

v=\frac{10 km}{10 min}=1 km/min

so the speed stays the same.

However, the velocity also takes into account the direction of motion: in the first leg, the direction is east, while in the second leg, the direction is south, therefore the average velocity has changed, since the direction has changed.

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3 years ago
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In EXACTLY 13 words explain how global warming happens on Earth.
inysia [295]

By pollution rotting the air and making is worse for us to breath

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3 years ago
In which scenario will the two objects have the least gravitational force between them?​
yawa3891 [41]

Answer:

A

Explanation:

7 0
3 years ago
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Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) what is the electric
Alex_Xolod [135]

The expression for the magnitude of the electric field between two uniform conducting plates is

E=\frac{V}{d}

Here, V is potential difference between plates and d is separation between plates.

As the potential 6.00 cm from the zero volt plate (and 4.00 cm from the other) is 420 V.

Therefore,

E = \frac{420 \ V}{6 \times 10^{-2} m } = 70 \times 10^2 \ V/m

Thus, the electric field strength between the plates is 7000 V/ m

8 0
3 years ago
charge, q1 =5.00μC, is at the origin, a second charge, q2= -3μC, is on the x-axis 0.800m from the origin. find the electric fiel
IRISSAK [1]

Answer:

Explanation:

Electric field due to charge at origin

= k Q / r²

k is a constant , Q is charge and r is distance

= 9 x 10⁹ x 5 x 10⁻⁶ / .5²

= 180 x 10³ N /C

In vector form

E₁ = 180 x 10³ j

Electric field due to q₂ charge

= 9 x 10⁹ x 3 x 10⁻⁶ /.5² + .8²

= 30.33 x 10³ N / C

It will have negative slope θ with x axis

Tan θ = .5 / √.5² + .8²

= .5 / .94

θ = 28°

E₂ = 30.33 x 10³ cos 28 i - 30.33 x 10³ sin28j

= 26.78 x 10³ i - 14.24 x 10³ j

Total electric field

E = E₁  + E₂

= 180 x 10³ j +26.78 x 10³ i - 14.24 x 10³ j

= 26.78 x 10³ i + 165.76 X 10³ j

magnitude

= √(26.78² + 165.76² ) x 10³ N /C

= 167.8 x 10³  N / C .

3 0
3 years ago
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