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3 years ago

What is thermal conductivity?

Physics

1 answer:

Vladimir79 [104]3 years ago

3 0

Thermal conductivity is the ability of a material to conduct heat.
hope this helped:)

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PLEASE HELP!!!!

weqwewe [10]

The answer is A. <span>Some work input is used to overcome friction. </span>

6 0

3 years ago

A roundabout in a fairground requires an input power of 2.5 kW when operating at a constant angular velocity of 0.47 rad s–1 . (

natita [175]

Answer:

Explanation:

Since the roundabout is rotating with uniform velocity ,

input power = frictional power

frictional power = 2.5 kW

frictional torque x angular velocity = 2.5 kW

frictional torque x .47 = 2.5 kW

frictional torque = 2.5 / .47 kN .m

= 5.32 kN . m

= 5 kN.m

b )

When power is switched off , it will decelerate because of frictional torque .

5 0

3 years ago

A suspended object A is attracted to a neutral wall. It's also attracted to a positively-charged object B. Which of the followin

olga2289 [7]

There are two particular cases, the first is when Object A is attracted to the neutral wall. This would indicate that the object is not neutral, as there is an attraction.

At the same time we know that Object A is attracted to an object B. And therefore, the load of A must be opposite to that of B. Remember that opposite charges attract each other. If the charge of object B is positive, then the charge of object A will be negative.

Option B is correct: It has a negative charge.

7 0

3 years ago

A railroad car is pulled through the distance of 960 m by a train that did 578 kJ of work during this pull.

Wittaler [7]

Answer:

Explanation:

The force supplied by the train can be found by using the formula

$f = \frac{w}{d} \\$

w is the workdone

d is the distance

From the question we have

$f = \frac{578000}{960} \\ = 602.083333...$

We have the final answer as

Hope this helps you

7 0

3 years ago

A heat engine does 200 j of work per cycle while exhausting 600 j of heat to the cold reservoir. what is the engine's thermal ef

AveGali [126]

The thermal efficiency of an engine is
$\eta= \frac{W}{Q}$
where
W is the work done by the engine
Q is the heat absorbed by the engine to do the work

In this problem, the work done by the engine is W=200 J, while the heat exhausted is Q=600 J, so the efficiency of the machine is
$\eta= \frac{W}{Q}= \frac{200 J}{600 J}=0.33 = 33 \%$

8 0

3 years ago