The correct matches are as follows:
<span>1. first nuclear reactor
</span>Fermi - an italian physicist who made the first nuclear reactor<span>
2. </span>1/0 η<span>
</span>atomic mass <span>
3. decaying nuclei
</span>fission<span> - nuclear reaction from a heavy elements to lighter elements
4. number of neutrons and protons
</span>neutron <span>
5. builds heavier elements
</span>fusion - nuclear reaction from two or more elements to a heavier element<span>
6. discovered radioactivity
</span>Curie<span>
7. unit of radiation
</span> Becquerel
Answer:
The magnitude of each charge is 
Explanation:
Suppose the two point charges are separated by 6 cm. The attractive force between them is 20 N.
We need to calculate the magnitude of each charge
Using formula of force
Where, q = charge
r = separation
Put the value into the formula
Hence, The magnitude of each charge is
The answer would Stratosphere because <span>1) The </span>troposphere<span> is the first </span>layer above<span> the surface and contains half of the Earth's </span>atmosphere<span>. Weather occurs in this </span>layer. 2) Many jet aircrafts fly in thestratosphere<span> because it is very stable. Also, the ozone </span>layer<span> absorbs harmful rays from the Sun</span>
Answer:
Explanation:
Let 100 m/s be the velocity of projection.
So horizontal component
= 100 cos42
= 74.31 m /s
Vertical component = - 100 sin 42 . in upward direction
66.91 m/s
Net displacement = 2.1 downwards ( + ve )
Using s = ut + 1/2 gt²
2.1 = - 66.91 t + .5 x 9.8 x t²
4.9 t² - 66.91 t - 2.1 = 0
t = 13.685 s
Horizontal distance covered
= 13.685 x 74.31
= 1016.93 m
If angle of projction is 40°
So horizontal component
= 100 cos40
= 76.60 m /s
Vertical component = - 100 sin 42 . in upward direction
64.27 m/s
Net displacement = 2.1 downwards ( + ve )
Using s = ut + 1/2 gt²
2.1 = -76.60 t + .5 x 9.8 x t²
4.9 t² - 76.60 t - 2.1 = 0
t = 15.659 s
Horizontal distance covered
= 15.659 x 76.60
= 1199.49 m
So horizontal range is increased , if angle of projection is increased .
