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3 years ago

Why would you make one of the addends a ten number when solving an addition problem?

1 answer:

7 0

By using a "tens number" as you refer to a multiple of ten. As a multiple of ten you can just add it to another number easier than a "ones number".

Does that answer your question?

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Use the laws of logarithms and the values given below to evaluate the logarithmic expression (picture provided)

nydimaria [60]

Answer: Option a.

Step-by-step explanation:

To solve the given exercise, you must keep on mind the law of logarithms shown below:

$log(a)-log(b)=log(\frac{a}{b})$

Therefore, by applying the law , you can rewrite the expression given, as following:

$log(\frac{5}{7})=log(5)-log(7)$

You know that:

$log5=0.6990\\log7=0.8451$

Then, when you substitute values, you obtain:

$0.6990-0.8451=-0.1461$

4 0

3 years ago

Read 2 more answers

Please help! I will mark you as brainliest if you answer correctly:)

padilas [110]

Answer: I think It's C i'm not sure tho. Sorry

5 0

2 years ago

Read 2 more answers

Find the indicated length

Setler79 [48]

Answer:

x=6

AC = 28

Step-by-step explanation:

4x+4= AC

4x +4 = 14 + 3x -4

4x-3x= 14-4-4

x = 6

AC = 4(6) +4 = 24+4 = 28

3 0

2 years ago

9/20

NISA [10]

For this case we must find the solution of the following quadratic equation:

$x ^ 2 + 5x + 7 = 0$

Where:

$a = 1\\b = 5\\c = 7$

Then, the solution is given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Substituting the values:

$x = \frac {-5 \pm \sqrt {5 ^ 2-4 (1) (7)}} {2 (1)}\\x = \frac {-5 \pm \sqrt {25-28}} {2}\\x = \frac {-5 \pm \sqrt {-3}} {2}$

By definition we have: $i ^ 2 = -1$

$x = \frac {-5 \pm \sqrt {3i ^ 2}} {2}\\x = \frac {-5 \pm i \sqrt {3}} {2}$

Thus, we have two complex roots.

Answer:

The equation has no real roots.

4 0

3 years ago

Use a single digit times a power of 10 to express the number 866,214,000,000

BartSMP [9]

Answer:

8.66214 x 10^11

Step-by-step explanation:

question may ask to round, so the answer may be simplified to 9 x 10^11

3 0

3 years ago