A 3.1 kg dog stands on an 18 kg flatboat and is 6.1 m from the shore. He walks 2.5 m on the boat toward shore and then stops. As
1 answer:
Answer:
The distance of dog from the shore is 3.97 m
Explanation:
given,
mass of the dog = 3.1 Kg
mass of the flatboat = 18 Kg
Distance from the shore = 6.1 m
dog moves on boat = 2.5 m
dog moves leftward and boat moves rightward.
If it's a frictionless system with no initial velocity, the center of mass doesn't move. Conservation of momentum, which = 0 in this case.
When dog move toward the shore a reactive force will act on the boat.
m_b i and m_d is mass of boat and mass of dog.
x_b and x_d is distance moved by the boat and the dog.
neglecting negative sign
x_b + x_d = 2.5
x_d = 2.133 m
The distance of dog from the shore is 6.1 – 2.133 = 3.97 m
The distance of dog from the shore is 3.97 m
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