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sasho [114]
3 years ago
7

Velocity of a body in circular or curved path is variable why give reasononly​

Physics
1 answer:
Svetradugi [14.3K]3 years ago
3 0

Because "velocity" means the speed and direction of the motion.

In circular motion, or motion on any curved path, the direction is constantly changing.  So even if the speed isn't changing, the <em>velocity</em> is.

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A well chosen lifetime activity is something that should hold a person's interest for a long time.
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true

Explanation:

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Calculate the number of images formed by two plane mirrors inclined at angel of 18 to each other
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Answer:

please give me brainlist and follow

Explanation:

Formula for number of images formed by two plane mirrors incident at an angle θ is n = 360∘θ. If n is even, the number of images is n-1, if n is an odd number of images.

4 0
3 years ago
An isotope is a version of the same element that differs in the composition of the A) atom. B) nucleus. C) particle. Eliminate D
crimeas [40]
The correct answer is B because isotopes have different numbers of neutrons, and neutrons are located in the nucleus

Hope this helps
5 0
3 years ago
Read 2 more answers
A tugboat tows a ship at a constant velocity. The tow harness consists of a single tow cable attached to the tugboat at point A
Y_Kistochka [10]

Answer:

The tensions in T_{BC} is approximately 4,934.2 lb and the tension in T_{BD} is approximately  6,035.7 lb

Explanation:

The given information are;

The angle formed by the two rope segments are;

The angle, Φ, formed by rope segment BC with the line AB extended to the center (midpoint) of the ship = 26.0°

The angle, θ, formed by rope segment BD with the line AB extended to the center (midpoint) of the ship = 21.0°

Therefore, we have;

The tension in rope segment BC = T_{BC}

The tension in rope segment BD = T_{BD}

The tension in rope segment AB = T_{AB} = Pulling force of tugboat = 1200 lb

By resolution of forces acting along the line A_F gives;

T_{BC} × cos(26.0°) + T_{BD} × cos(21.0°) = T_{AB} = 1200 lb

T_{BC} × cos(26.0°) + T_{BD} × cos(21.0°) = 1200 lb............(1)

Similarly, we have for equilibrium, the sum of the forces acting perpendicular to tow cable = 0, therefore, we have;

T_{BC} × sin(26.0°) + T_{BD} × sin(21.0°) = 0...........................(2)

Which gives;

T_{BC} × sin(26.0°) = - T_{BD} × sin(21.0°)

T_{BC} = - T_{BD} × sin(21.0°)/(sin(26.0°))  ≈ - T_{BD} × 0.8175

Substituting the value of, T_{BC}, in equation (1), gives;

- T_{BD} × 0.8175 × cos(26.0°) + T_{BD} × cos(21.0°) = 1200 lb

- T_{BD} × 0.7348  + T_{BD} ×0.9336 = 1200 lb

T_{BD} ×0.1988 = 1200 lb

T_{BD} ≈ 1200 lb/0.1988 = 6,035.6938 lb

T_{BD} ≈ 6,035.6938 lb

T_{BC} ≈ - T_{BD} × 0.8175 = 6,035.6938 × 0.8175 = -4934.1733 lb

T_{BC} ≈ -4934.1733 lb

From which we have;

The tensions in T_{BC} ≈ -4934.2 lb and  T_{BD} ≈ 6,035.7 lb.

8 0
3 years ago
Which of the following is true about all electromagnetic waves in a vacuum
Helen [10]
Electro waves in a vacuum air is deals with this and electricity when the air and the electricity it  makes electro magnets.
4 0
3 years ago
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