Area of a triangle = 1/2 ab sinC
In this equation the angle C is between the two adjacent sides ab
Since the lengths are equal we can call them both X
Hence 254= 1/2 (x)(x) sin53
By simplifying 508 = (x^2) sin53
So therefore x is the square root of 508 divided by sin53 which means the length of the sides is 35.8km to 3 significant figures
Answer:
x^3+7x^2−9x−63
Step-by-step explanation:
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Answer:
Distance between two points= √(x2-x1)²+(y2-y1)²
D= 15units
Let "k" be the y-coordinate of A
A(-6,k)
B(3,2)
15= √(3--6)²+(2-k)²
Taking square of both sides to eliminate the square root.
15²=(9)²+(2-k)²
225=81+4-4k+k²
k²-4k - 140=0
Using Quadratic Formula to evaluate
k= 14 or k=-10
The Possible coordinates of A are
(-6,14) or (-6,-10)
<h2>727</h2>
Step-by-step explanation:
Let us denote the three digit number by
, where
is the hundreds digit,
is the tens digit and
is the ones digit.
Hundreds digit =
= Ones digit = 
Sum of digits = 
So, 
On exchanging tens and ones digit, value increases by 45. So
is 45 greater than
.



∴ Required number is 727