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Daniel [21]
3 years ago
6

What mass of lead (density 11.4 g/cm3) would have an identical volume to 20.1 g of mercury (density 13.6 g/cm3)?

Chemistry
2 answers:
oksano4ka [1.4K]3 years ago
8 0
In order to determine the mass of lead, Pb, that would have an identical volume as 20.1 g of mercury, Hg, we first get the equivalent volume of 20.1 g of mercury. This can be done by using the given density of mercury which is equal to 13.6 g/cm^3. This is shown in the following equation:

20.1 g Hg/ 13.6g/cm^3 = 1.4779 cm^3 of Hg

Consequently, we use this obtained volume which is the target volume for lead. Again, we make use of the density of the substance, in this case, lead has a density of 11.4 g/cm^3. The resulting equation is then:

11.4 g/cm^3 x 1.4779 cm^3 = 16.8485 g of Pb

Thus, the amount of lead that has an identical volume as 20.1 g of mercury is 16.8485 g Pb.   
inysia [295]3 years ago
3 0

<u>Answer:</u> The mass of lead is 16.872 g

<u>Explanation:</u>

To calculate mass of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}      ......(1)

  • <u>For Mercury:</u>

Density of mercury = 13.6g/cm^3

Mass of mercury = 20.1 g

Putting values in equation 1, we get:

13.6g/cm^3=\frac{20.1g}{\text{Volume of mercury}}\\\\\text{Volume of mercury}=1.48cm^3

The volume of mercury is 1.48cm^3 which is equal to the lead sample.

  • <u>For lead:</u>

We are given:

Density of lead = 11.4g/cm^3

Volume of lead = 1.48cm^3

Putting values in equation 1, we get:

11.4g/cm^3=\frac{\text{Mass of lead}}{1.48cm^3}\\\\\text{Mass of lead}=16.872g

Hence, the mass of lead is 16.872 g

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