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3 years ago

What mass of lead (density 11.4 g/cm3) would have an identical volume to 20.1 g of mercury (density 13.6 g/cm3)?

2 answers:

8 0

In order to determine the mass of lead, Pb, that would have an identical volume as 20.1 g of mercury, Hg, we first get the equivalent volume of 20.1 g of mercury. This can be done by using the given density of mercury which is equal to 13.6 g/cm^3. This is shown in the following equation:

20.1 g Hg/ 13.6g/cm^3 = 1.4779 cm^3 of Hg

Consequently, we use this obtained volume which is the target volume for lead. Again, we make use of the density of the substance, in this case, lead has a density of 11.4 g/cm^3. The resulting equation is then:

11.4 g/cm^3 x 1.4779 cm^3 = 16.8485 g of Pb

Thus, the amount of lead that has an identical volume as 20.1 g of mercury is 16.8485 g Pb.

inysia [295]3 years ago

3 0

Answer: The mass of lead is 16.872 g

Explanation:

To calculate mass of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$ ......(1)

For Mercury:

Density of mercury = $13.6g/cm^3$

Mass of mercury = 20.1 g

Putting values in equation 1, we get:

$13.6g/cm^3=\frac{20.1g}{\text{Volume of mercury}}\\\\\text{Volume of mercury}=1.48cm^3$

The volume of mercury is $1.48cm^3$ which is equal to the lead sample.

For lead:

We are given:

Density of lead = $11.4g/cm^3$

Volume of lead = $1.48cm^3$

Putting values in equation 1, we get:

$11.4g/cm^3=\frac{\text{Mass of lead}}{1.48cm^3}\\\\\text{Mass of lead}=16.872g$

Hence, the mass of lead is 16.872 g

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Answer:

a. NADH, FADH2

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The reduced coenzyme that is generated in the citric acid cycles are NADH and FADH2. These coenzymes feed electrons in the electron transport chain which moves through electron acceptors present in the ETC.

The final electron acceptor in the electron transport chains is oxygen which converts into H2O. This movement of electron through ETS allows the movement of H+ ions from the mitochondrial matrix to intermembrane space.

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3 years ago

The diameter of a carbon atom is approximately 144 pm. Assuming a nanocontainer has a simple cubic structure and have an edge le

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To answer this question, you need to understand the naming of meter unit system. The unit pm stands for pico meter which was 1/1000 of nanometer. Then, the calculation would be:

Number of atom= container length / atom diameter
Number of atom = 25 nm x (1000pm/nm) / 144pm= 173.6 atom

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3 years ago

If you were given a 16.0 ml sample of solution A, describe how you could determine the mass of the sample using only your graph

rewona [7]

A density of the substance is an intrinsic property. Each substance has its own value of density, and it is constant. Since density is equal to mass over volume, a graph of mass vs volume would have a constant slope equal to density. So, it will be a linear graph. The mass is in the y-axis, and the volume is on the x-axis. Locate V = 16 mL on the x-axis, project it upwards until it intersects with the linear graph, then, move towards the left to determine the corresponding y-value, represented by the mass.

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4 years ago

12.5 g of copper are reacted with an excess of chlorine gas, and 25.4 g of copper(II) chloride are

Alika [10]

Answer:

Percent yield = 94.5%

Theoretical yield = 26.89 g

Explanation:

Given data:

Mass of copper = 12.5 g

Mass of copper chloride produced = 25.4 g

Theoretical yield = ?

Percent yield = ?

Solution:

Cu + Cl₂ → CuCl₂

Number of moles of Copper:

Number of moles = mass/ molar mass

Number of moles = 12.5 g/ 63.55 g/mol

Number of moles = 0.2 mol

Now we will compare the moles of copper with copper chloride.

Cu : CuCl₂

1 : 1

0.2 : 0.2

Theoretical yield:

Mass of copper chloride:

Mass = Number of moles × molar mass

Mass = 0.2 mol × 134.45 g/mol

Mass = 26.89 g

Percent yield:

Percent yield = Actual yield / theoretical yield × 100

Percent yield = 25.4 g/26.89 g × 100

Percent yield = 94.5%

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4 years ago

Iron has many isotopes but only 4 are found in significant amounts in naturally found mixtures. The amounts by mass percent are:

AnnZ [28]

Answer:

The average mass of iron to be is 54.76 amu.

Explanation:

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

Mass of Fe-54 isotope = 53.9396 amu

Percentage abundance of Fe-54 = 5.845%

Fractional abundance of Fe-54 = 0.05845

Mass of Fe-56 isotope = 55.9349 amu

Percentage abundance of Fe-56 = 91.754 %

Fractional abundance of Fe-56= 0.91754

Mass of Fe-57 isotope = 56.9354 amu

Percentage abundance of Fe-57 = 2.119%

Fractional abundance of Fe-57 = 0.002119

Mass of Fe-58 isotope = 57.9333 amu

Percentage abundance of Fe-58 = 0.282%

Fractional abundance of Fe-58 = 0.00282

Average atomic mass of iron :

$=53.9396 amu\times 0.05845+55.9349 amu\times 0.91754 +56.9354 amu\times 0.002119 + 57.9333 amu\times 0.00282=54.76 amu$

The average mass of iron to be is 54.76 amu.

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3 years ago