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Elena L [17]
2 years ago
7

What is the energy of an electromagnetic wave that has a wavelength of 0.035 m?

Chemistry
1 answer:
IgorC [24]2 years ago
8 0
It seems that you have missed the given choices for this question. But anyway, here is the correct answer. The energy of an electromagnetic wave that has a wavelength of 0.035m is 5.68E-24 J. Hope this is the answer you are looking for. Other choices of this question include the following: 2.16E-35 J, 1.14E7 J, and 8.62E9 J. Thanks for posting your question.
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Industrial ethanol (CH3CH2OH) is produced by a catalytic reaction of ethylene (CH2═CH2) with water at high pressures and tempera
Natasha2012 [34]

Answer:

using bond energies = - 37 kJ

using enthalpies of formation = - 45.7 kJ

Explanation:

From the reaction;

CH2═CH2(g) + H2O(g) -------> CH3CH2OH(g)

From the above reaction; there are 4 (C-H) bonds , 1 ( C=C) and 2 (H-O) of ethene which forms 5(C-H) bonds, 1 (C-C) and 1 (C-O) and 1(H-O) bonds.

Using Bond Energies; the heat of the reaction can be written as:

\delta H^0_ {rxn}= ∑ energy of old bond breaking + ∑ energies of the new bond formation.

\delta H^0_ {rxn}= ∑ [(4 * BE_{C-H})  + BE_{C-C}) +  + BE_{O-H})]+ ∑ [(5 * BE_{C-H}) + BE_{C-C}) + BE_{O-H}+ BE_{C-O})]

\delta H^0_ {rxn}= ∑[4*413 kJ)+(614kJ)+(2*647kJ]+ ∑ (5*-413kJ)+(-347kJ)+(-467kJ)+(-358kJ)]

\delta H^0_ {rxn}=  -37 kJ

To calculate the heats of reaction by using enthalpies of formation; we have:

\delta H^0_ {rxn}= ∑ \delta H^0_ {products} -  ∑ \delta H^0_ {reactants}

\delta H^0_ {rxn}= ∑ \delta H^0_ {CH_3CH_2OH} - ∑ \delta H^0_ {CH_2=CH_2+H_2O}

\delta H^0_ {rxn}=  (-235.1 kJ) - [(+52.47 kJ) + (-241.826 kJ)]

\delta H^0_ {rxn}=  -45.7 kJ

6 0
3 years ago
There is a mixture of three gases. We know the total pressure is 2.50 atmosphere and the pressure of the oxygen and the nitrogen
Viktor [21]

Answer:

1.14 atm and 1.139 mol

Explanation:

The <em>total pressure</em> of the container is equal to the <u>sum of the partial pressure of the three gasses</u>:

  • P = Poxygen + Pnitrogen + Pcarbon dioxide
  • 2.50 atm = 0.52 + 0.84 + Pcarbon dioxide

Now we <u>solve for the pressure of carbon dioxide</u>:

  • Pcarbon dioxide = 1.14 atm

To c<u>alculate the number of CO₂ moles </u>we use <em>PV=nRT</em>:

  • P = 1.14 atm
  • V = 25.0 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 32 °C ⇒ 32 + 273.16 = 305.16 K

1.14 atm * 25.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 305.16 K

  • n = 1.139 mol
5 0
3 years ago
What are four chemical and physical properties of phosphorus?
DedPeter [7]

Answer:

Properties: The melting point of phosphorus (white) is 44.1°C, boiling point (white) is 280°C, specific gravity (white) is 1.82, (red) 2.20, (black) 2.25-2.69, with a valence of 3 or 5. There are four allotropic forms of phosphorus: two forms of white (or yellow), red, and black (or violet).Oct 7, 2019

Atomic Number: 15

Atomic Weight: 30.973762

Explanation:

: )

8 0
2 years ago
Read 2 more answers
7 Los organismos que se alimentan de material orgánico incluye:<br>​
kipiarov [429]

Answer:

que

Explanation:

8 0
3 years ago
Determine the ground-state electron configuration for each of the following elements: A. chlorine ______________________________
ki77a [65]

In ground-state electron configuration, the<u> principal quantum number</u> (n), <u>the orbital</u> (s, p, d, or f), and the total number of <u>electrons</u> are used to represent electron configurations.

Case 1 Ground-state electron configuration of elements.

A) Chlorine: 1s²2s²2p^{6}3s²3p^{5}

B) Cesium: 1s² 2s²2p⁶ 3s²3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶ 6s¹

C) Vanadium: 1s²2s²2p⁶3s²3p⁶3d³4s²

D) Rhenium: 1s² 2s² 2p⁶ 3s² 3p⁶3d¹⁰ 4s²4p⁶ 4d¹⁰ 5s² 5p⁶ 4f¹⁴ 5d⁵ 6s²

Case 2 : Number of valence electron in atoms

A) Sn -Tin - Four valence electrons

B) La - Lanthanum - Three valence electrons

C) Mn - Manganese - Seven valence electrons

D) Zn- Zinc - Two valence electrons

Case 3 Ground-state electronic configuration of ions

A) Co⁺³ : 1s² 2s² 2p⁶ 3s² 3p⁶4s¹3d⁵

B) Mo⁺² : 1s² 2s² 2p⁶3s²3p⁶ 4s² 3d¹⁰ 4p⁶5s² 4d²

C) Ra⁺² : 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 4f¹⁴ 5s² 5p⁶ 5d¹⁰ 6s² 6p⁶

D) I⁻ : 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶

Learn more about Quantum numbers here brainly.com/question/2292596

#SPJ4

8 0
2 years ago
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