Answer:
<h2>
<em>Option</em><em> </em><em>C</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>correct </em><em>option</em><em>.</em></h2>
<em>The</em><em> </em><em>Valence </em><em>electrons</em><em> </em><em>in</em><em> </em><em>S</em>
<em>Expla</em><em>nation</em><em>:</em>
<em>Sulphur</em><em> </em><em>has</em><em> </em><em>highest</em><em> </em><em>effect</em><em>ive</em><em> </em><em>nuclear</em><em> </em><em>charge</em><em> </em><em>as</em><em> </em><em>in </em><em>a</em><em> </em><em>period</em><em> </em><em>there</em><em> </em><em>is </em><em>increase</em><em> </em><em>in</em><em> </em><em>effective</em><em> </em><em>nuclear</em><em> </em><em>charge</em><em> </em><em>from</em><em> </em><em>left </em><em>to</em><em> </em><em>right.Sulphur</em><em> </em><em>is </em><em>in </em><em>the</em><em> </em><em>end </em><em>in</em><em> </em><em>a</em><em> </em><em>period</em><em> </em><em>leaving</em><em> </em><em>Mg</em><em> </em><em>and</em><em> </em><em>Al</em><em> </em><em>in</em><em> </em><em>left </em><em>side.</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>helps.</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>
I'll see what I can do here...
1) Nonmetal
2) Calcium (Ca), chemical element, one of the alkaline-earth metals of Group 2 (IIa) of the periodic table.
3) Hafnium
4) 204.3833 u
5) Not sure what you're asking, but oble gas, any of the seven chemical elements that make up Group 18 (VIIIa) of the periodic table. The elements are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn), and oganesson (Og)
6) The metalloids; boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te), polonium (Po) and astatine (At)
7) The Actinide series contains elements with atomic numbers 89 to 103 and is the third group in the periodic table.
8) 33
9) 88
10) 30
Hope this helps!
B- is the answer
Hope this helps
Have a nice day~
Answer:
b. Beta emission, beta emission
Explanation:
A factor to consider when deciding whether a particular nuclide will undergo this or that type of radioactive decay is to consider its neutron:proton ratio (N/P).
Now let us look at the N/P ratio of each atom;
For B-13, there are 8 neutrons and five protons N/P ratio = 8/5 = 1.6
For Au-188 there are 109 neutrons and 79 protons N/P ratio = 109/79=1.4
For B-13, the N/P ratio lies beyond the belt of stability hence it undergoes beta emission to decrease its N/P ratio.
For Au-188, its N/P ratio also lies above the belt of stability which is 1:1 hence it also undergoes beta emission in order to attain a lower N/P ratio.
Reduction half reaction: Cu²⁺(aq) + 2e⁻ → Cu⁰(s).
Oxidation half reaction: NO₂⁻(aq) + H₂O(l) → NO₃⁻(aq) + 2H⁺(aq) + 2e⁻.
Balanced chemical reaction:
Cu²⁺(aq) + NO₂⁻(aq) + H₂O(l) → Cu(s) + NO₃⁻(aq) + 2H⁺(aq).
Copper is reduced from oxidation number +2 (Cu²⁺) to oxidation number 0 (Cu) and nitrogen is oxidized from oxidation number +3 (in NO₂⁻) to oxidation number +5 (in NO₃⁻).
