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3 years ago

Momentum has a _____. a. direction only b. magnitude only c. direction and magnitude

Physics

2 answers:

Elina [12.6K]3 years ago

8 0

C. Direction and Magnitude

It is a vector quantity

weeeeeb [17]3 years ago

5 0

Momentum has both direction and magnitude.

It is a vector quantity.

Its formula is = Mass * Velocity, Mass you know is associated with size and velocity of course is associated with direction.

C. direction and magnitude

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How are the words season,equinox and solstice related ??

Rasek [7]

They are all related to what time of year it is.

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3 years ago

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Two guitars are playing together producing a beat frequency. The first guitar is playing at a frequency of 867 Hz and the beat i

vlabodo [156]

Answer:

The possible frequency of guitar are 842 HZ and 892 HZ.

Explanation:

given the beat frequency = $\frac{1}{0.04}$ = 25 HZ

we know that beat frequency = difference of frequencies of two instruments

therfore 25 = x-867 or 25 = 867-x

therefore x = 842 or 892

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4 years ago

a 1150 kg car is on a 8.70 hill. using x-y axis tilted down the plane, what is the x-component of the normal force(unit=N)

rodikova [14]

The x-component of the normal force is equal to <u>1706.45 N.</u>

Why?

To solve the problem, and since there is no additional information, we can safely assume that the x-axis is parallalel to the hill surface and the y-axis is perpendicular to the x-axis. Knowing that, we can calculate the components of the normal force (or weight for this case), using the following formulas:

$N_{x}=W*Sin(\alpha)=mg*Sin(\alpha)\\\\N_{y}=W*Cos(\alpha)=mg*Cos(\alpha)$

Now, using the given information, we have:

$mass=m=1150Kg\\\alpha=8.70\°\\g=9.81\frac{m}{s^{2}}$

Calculating, we have:

$N_{x}=mg*Sin(\alpha)$

$N_{x}=1150Kg*9.81\frac{m}{s^{2}}*Sin(8.70\°)\\\\N_{x}=11281.5\frac{Kg.m}{s^{2} }*Sin(8.70\°)=1706.45\frac{Kg.m}{s^{2} }=1706.45.23N$

Hence, we have that the x-component of the normal force is equal to <u>1706.45 N.</u>

Have a nice day!

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4 years ago

Will give Brainliest!! Question attached.

ss7ja [257]

Answer:

im pretty sure it is 3.0 K

Explanation:

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3 years ago

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Suppose a skydiver (mass =100kg) is falling towards the earth. When the skydiver is 80 m above the earth he is moving at 60 m/s

goblinko [34]

Answer:

The total mechanical energy of the skydiver is, E = 96402.6 J

Explanation:

Given data,

The mass of the skydiver, m = 100 kg

The speed of the skydiver at 80 m height, v = 60 m/s

The initial velocity of the skydiver, u = 0

Using the III equations of motion,

v² = u² + 2gs

s = v²/2g

Substituting the given values,

s = ½ 60²/ 9.8

= 18.37 m

Hence the initial total distance of the skydiver from the ground initially,

h = s + d

= 18.37 + 80

= 98.37 m

Since the total mechanical energy of a system is conserved, the total mechanical energy of the skydiver at height 'h' is equal to the total mechanical energy at height 'd'.

E = P.E + K.E

= mgh + ½ mu²

= 100 x 9.8 x 98.37 ( ∵ u = 0)

= 96402.6 J

Hence, the total mechanical energy of the skydiver is, E = 96402.6 J

5 0

3 years ago