Ok so basically you have to look at the work and then look at the work and then it will show
Answer:the answer is D
Explanation its the blue one with the kind rectangle shaped ones
You just told us that the acceleration is constant, and we believed you. So if we draw a graph of it, and it never gets any higher or lower than 5 m/s², then the graph is a straight horizontal line.
Answer:
Multiply the time by the acceleration due to gravity to find the velocity when the object hits the ground. If it takes 9.9 seconds for the object to hit the ground, its velocity is (1.01 s)*(9.8 m/s^2), or 9.9 m/s.
Explanation:really sorry if it wrong,i mean reallyyyyy
Answer:
(a) Magnetic field at the center of the loop is 4.08 x 10⁻⁵ T
(b) Magnetic field at the axis of the loop is 5.09 x 10⁻⁹ T
Explanation:
Given :
Diameter of the circular loop = 2 cm
Radius of the circular loop, R = 1 cm = 0.01 m
Current flowing through the circular wire, I = 650 mA = 650 x 10⁻³ A
(a) Magnetic field at the center of circular loop is determine by the relation:
![B=\frac{\mu_{0}I }{2R}](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B%5Cmu_%7B0%7DI%20%7D%7B2R%7D)
Here μ₀ is vacuum permeability constant and its value is 4π x 10⁻⁷ T m²/A.
Substitute the suitable values in the above equation.
![B=\frac{4\pi\times10^{-7}\times650\times10^{-3} }{2\times0.01}](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B4%5Cpi%5Ctimes10%5E%7B-7%7D%5Ctimes650%5Ctimes10%5E%7B-3%7D%20%20%20%20%7D%7B2%5Ctimes0.01%7D)
B = 4.08 x 10⁻⁵ T
(b) Distance from the center of the loop, z = 20 cm = 0.2 m
Magnetic field at the point on the axis of the loop is determine by the relation:
![B=\frac{\mu_{0}IR^{2} }{2(z^{2}+R^{2})^{3/2} }](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B%5Cmu_%7B0%7DIR%5E%7B2%7D%20%20%7D%7B2%28z%5E%7B2%7D%2BR%5E%7B2%7D%29%5E%7B3%2F2%7D%20%20%20%7D)
![B=\frac{4\pi\times10^{-7}\times650\times10^{-3}\times (0.01)^{2} }{2((0.2)^{2}+(0.01)^{2})^{3/2} }](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B4%5Cpi%5Ctimes10%5E%7B-7%7D%5Ctimes650%5Ctimes10%5E%7B-3%7D%5Ctimes%20%280.01%29%5E%7B2%7D%20%20%7D%7B2%28%280.2%29%5E%7B2%7D%2B%280.01%29%5E%7B2%7D%29%5E%7B3%2F2%7D%20%20%20%7D)
B = 5.09 x 10⁻⁹ T